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Category: Geometry

Evaluate-tan-d-

Question Number 119 by novrya last updated on 25/Jan/15 Evaluatetanθdθ Answered by rajabhay last updated on 06/Dec/14 tanθ=t2$$\mathrm{sec}^{\mathrm{2}} \theta\:{d}\theta=\mathrm{2}{t}\:{dt},\:\mathrm{sec}^{\mathrm{2}} \theta=\mathrm{1}+{t}^{\mathrm{4}} \