Question Number 71593 by TawaTawa last updated on 17/Oct/19 Answered by mr W last updated on 17/Oct/19 Commented by mr W last updated on 17/Oct/19…
Question Number 6054 by Rasheed Soomro last updated on 11/Jun/16 $$\mathcal{D}{etermine}\:{distance}\:{between} \\ $$$${opposite}\:{corners}\:\:{of}\:{a}\:{cubic} \\ $$$${room}\:{of}\:{dimention}\:{x}\:{units}. \\ $$$$ \\ $$ Commented by Yozzii last updated on…
Question Number 6056 by Rasheed Soomro last updated on 11/Jun/16 Commented by Rasheed Soomro last updated on 11/Jun/16 $$\boldsymbol{\mathrm{I}}\:\:{and}\:\boldsymbol{\mathrm{H}}\:{are}\:{mid}-{points}\:{of}\:{line}\:{segments}. \\ $$$$\boldsymbol{\mathrm{E}}\:\:{is}\:{the}\:{centre}\:{of}\:{the}\:{square}. \\ $$$${center}\:{of}\:{both}\:{arcs}\:{is}\:\boldsymbol{\mathrm{B}}. \\ $$…
Question Number 71572 by TawaTawa last updated on 17/Oct/19 Commented by TawaTawa last updated on 17/Oct/19 $$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\:\mathrm{How}\:? \\ $$ Answered by Kunal12588 last updated on…
Question Number 137088 by I want to learn more last updated on 29/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 71538 by mr W last updated on 16/Oct/19 Commented by mr W last updated on 16/Oct/19 $${find}\:{the}\:{position}\:{of}\:{center}\:{of}\:{mass} \\ $$$${of}\:{the}\:{parabolic}\:{arc} \\ $$ Answered by…
Question Number 5998 by Kasih last updated on 09/Jun/16 $${determine}\:{equation}\:{of}\:{circle}\:{that}\:{offensive}\:{the} \\ $$$${both}\:{of}\:{coordinate}\:{and}\:{through}\:\left(\mathrm{2},−\mathrm{1}\right) \\ $$ Commented by Rasheed Soomro last updated on 09/Jun/16 $${What}\:{do}\:{you}\:{mean}\:{by}\:“{offensive}''? \\ $$…
Question Number 5982 by Kasih last updated on 08/Jun/16 $${the}\:{center}\:{of}\:{circle}\:{in}\:\mathrm{2}{x}+{y}−\mathrm{11}=\mathrm{0} \\ $$$${determine}\:{the}\:{equation}\:{of}\:{circle}\:{that} \\ $$$${passing}\:{through}\:\left(−\mathrm{1},\mathrm{3}\right),\left(\mathrm{7},−\mathrm{1}\right) \\ $$ Commented by Rasheed Soomro last updated on 08/Jun/16 $${the}\:{center}\:{of}\:{circle}\:{in}\:\mathrm{2}{x}+{y}−\mathrm{11}=\mathrm{0}…
Question Number 71517 by TawaTawa last updated on 16/Oct/19 Answered by mind is power last updated on 16/Oct/19 $$\mathrm{AD}=\mathrm{x} \\ $$$$\frac{\mathrm{x}}{\mathrm{sin}\left(\theta\right)}=\frac{\mathrm{DC}}{\mathrm{sin}\left(\theta\right)}\Rightarrow\mathrm{1}=\frac{\mathrm{x}}{\mathrm{DC}} \\ $$$$\frac{\mathrm{x}}{\mathrm{sin}\left(\mathrm{3}\theta\right)}=\frac{\mathrm{DC}}{\mathrm{sin}\left(\mathrm{10}\theta\right)}\Rightarrow\frac{\mathrm{x}}{\mathrm{DC}}=\frac{\mathrm{sin}\left(\mathrm{3}\theta\right)}{\mathrm{sin}\left(\mathrm{10}\theta\right)} \\ $$$$…
Question Number 136990 by EDWIN88 last updated on 28/Mar/21 $$ \\ $$Given a cube ABCD.EFGH where point Z is the midpoint of AE, point R…