Question Number 5447 by 3 last updated on 15/May/16 $$\mathrm{6}/\mathrm{8} \\ $$$$ \\ $$ Answered by FilupSmith last updated on 15/May/16 $$\frac{\mathrm{6}}{\mathrm{8}}=\frac{\mathrm{2}×\mathrm{3}}{\mathrm{2}×\mathrm{4}} \\ $$$$=\frac{\mathrm{2}}{\mathrm{2}}×\frac{\mathrm{3}}{\mathrm{4}} \\…
Question Number 5441 by Rasheed Soomro last updated on 15/May/16 Commented by Rasheed Soomro last updated on 15/May/16 $$\left(\mathrm{a}\right)\:\mathrm{AB}=\mathrm{a}\:,\:\mathrm{BC}=\mathrm{b}\:,\:\mathrm{Area}\:\mathrm{EFGH}=? \\ $$$$ \\ $$$$\left(\mathrm{b}\right)\:\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{if}\:\mathrm{ABCD}\:\mathrm{is}\:\mathrm{a}\:\mathrm{rectangle}\: \\ $$$$\:\:\:\:\:\:\:\:\mathrm{then}\:\mathrm{EFGH}\:\mathrm{is}\:\mathrm{a}\:\mathrm{parallelogram}.…
Question Number 5417 by FilupSmith last updated on 14/May/16 $$\mathrm{Prove},\:\mathrm{or}\:\mathrm{disprove},\:\mathrm{that}\:\mathrm{the}\:\mathrm{circle} \\ $$$$\mathrm{has}\:\mathrm{the}\:\mathrm{largest}\:{Perimiter}\:\mathrm{over}\:\mathrm{all} \\ $$$$\mathrm{natural}\:\mathrm{shapes}\:\mathrm{that}\:\mathrm{have}\:\mathrm{area}\:{A} \\ $$ Commented by Rasheed Soomro last updated on 14/May/16 $$\mathrm{I}\:\mathrm{think}\:\mathrm{that}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{has}\:\mathrm{the}\:\mathrm{smallest}…
Question Number 5410 by FilupSmith last updated on 14/May/16 Commented by FilupSmith last updated on 14/May/16 $$\mathrm{An}\:\mathrm{equilateral}\:\mathrm{triangle}\:\mathrm{with}\:\mathrm{sides}\:\mathrm{of} \\ $$$$\mathrm{length}\:{L},\:\mathrm{contains}\:\mathrm{a}\:\mathrm{rectangle}\:\mathrm{with} \\ $$$$\mathrm{lengths}\:{a}\:\mathrm{and}\:{b}. \\ $$$$ \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{size}\:\mathrm{of}\:\mathrm{the}\:\mathrm{rectangle}?…
Question Number 5398 by FilupSmith last updated on 13/May/16 $$\mathrm{If}\:\mathrm{we}\:\mathrm{have}\:\mathrm{an}\:{n}−\mathrm{dimensional}\:\mathrm{cube}. \\ $$$$\mathrm{How}\:\mathrm{do}\:\mathrm{we}\:\mathrm{find}\:\mathrm{its}\:'{volume}'? \\ $$ Commented by Rasheed Soomro last updated on 13/May/16 $$\mathrm{Suppose}\:\mathrm{s}\:\:\mathrm{is}\:\mathrm{measure}\:\mathrm{of}\:\mathrm{side}\:\mathrm{of}\: \\ $$$$\mathrm{n}-\mathrm{dimensional}\:\mathrm{cube}.…
Question Number 5381 by Rasheed Soomro last updated on 12/May/16 Commented by Rasheed Soomro last updated on 15/May/16 $$\bigtriangleup\mathrm{ABC}\sim\bigtriangleup\mathrm{EFD} \\ $$ Terms of Service Privacy…
Question Number 5354 by Rasheed Soomro last updated on 11/May/16 Commented by Rasheed Soomro last updated on 11/May/16 $$\mathrm{ABCD}\:\mathrm{and}\:\mathrm{EFGH}\:\mathrm{are}\:\mathrm{squares}\:\mathrm{in} \\ $$$$\mathrm{above}\:\mathrm{figure}.\mathrm{The}\:\mathrm{centres}\:\mathrm{of}\:\mathrm{the}\:\:\mathrm{arcs}\: \\ $$$$\mathrm{are}\:\mathrm{vertices}\:\mathrm{of}\:\mathrm{the}\:\mathrm{external}\:\mathrm{square}. \\ $$$$\mathrm{If}\:\:\mathrm{EF}=\mathrm{t}\:\mathrm{then}\:\mathrm{AB}=?…
Question Number 5350 by sanusihammed last updated on 09/May/16 $${Suppose}\:{the}\:{radius}\:{of}\:{the}\:{earth}\:{is}\:\mathrm{6400}{km}.\:{the}\:{acceleration}\: \\ $$$${of}\:{a}\:{person}\:{at}\:{latitude}\:\mathrm{60}°\:{due}\:{to}\:{the}\:{earth}\:{rotation}\:{is}\:? \\ $$$$ \\ $$$$\left({a}\right)\:\mathrm{0}.\mathrm{034}{m}/{s}^{\mathrm{2}} \\ $$$$\left({b}\right)\:\mathrm{232}.\mathrm{7}{m}/{s}^{\mathrm{2}} \\ $$$$\left({c}\right)\:\mathrm{0}.\mathrm{0169}{m}/{s}^{\mathrm{2}} \\ $$$$\left({d}\right)\:\mathrm{465}.\mathrm{4}{m}/{s}^{\mathrm{2}} \\ $$$$ \\…
Question Number 136415 by ajfour last updated on 21/Mar/21 Commented by ajfour last updated on 21/Mar/21 $${Find}\:{maximum}\:{area}\:{of} \\ $$$$\bigtriangleup{APQ}\:\:{in}\:{terms}\:{of}\:{a},{b},{c},{h}. \\ $$ Answered by mr W…
Question Number 5341 by FilupSmith last updated on 09/May/16 $$\mathrm{Three}\:\mathrm{circles}\:\mathrm{with}\:\mathrm{radius}\:{r} \\ $$$$\mathrm{The}\:\mathrm{circles}\:\mathrm{have}\:\mathrm{equations}: \\ $$$${c}_{\mathrm{1}} :\:\:\:\:\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={r}^{\mathrm{2}} \\ $$$${c}_{\mathrm{2}} :\:\:\:\:\:\left({x}−{r}\right)^{\mathrm{2}} +{y}^{\mathrm{2}} ={r}^{\mathrm{2}} \\ $$$${c}_{\mathrm{3}} :\:\:\:\:\:{x}^{\mathrm{2}}…