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Question Number 73503 by ajfour last updated on 13/Nov/19 Commented by ajfour last updated on 13/Nov/19 $${Find}\:{the}\:{illuminated}\:{curved} \\ $$$${area}\:{of}\:{cone}\:{with}\:{radius}\:{a},\:{and} \\ $$$${altitude}\:{a}\sqrt{\mathrm{3}}\:.\:{Only}\:{the}\:{right}\:{half} \\ $$$${of}\:{cone}\:{is}\:{there}\:{with}\:{left}\:{half} \\ $$$${covered}\:{but}\:{with}\:{a}\:{largest}\:{circular}…
Question Number 73499 by TawaTawa last updated on 13/Nov/19 Commented by MJS last updated on 13/Nov/19 $$\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{unique}\:\mathrm{if}\:\mathrm{we}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mid{OP}\mid=\mathrm{2}{r} \\ $$ Commented by TawaTawa last updated on…
Question Number 7945 by Rasheed Soomro last updated on 25/Sep/16 Commented by Rasheed Soomro last updated on 25/Sep/16 $${In}\:{above}\:{figure}\:{AF}\:,{a}\:{diameter}\:{of}\:{the} \\ $$$${circle}\:{with}\:{centre}\:{G}\:{has}\:{been}\:{trisected} \\ $$$${at}\:{B}\:\&\:{D}\:\left({i}-{e}\:{AB}={BD}={DF}\right) \\ $$$${Is}\:{there}\:{any}\:{point}\:{H}\:{on}\:{the}\:{circle}\:{for}…
Question Number 7935 by tawakalitu last updated on 24/Sep/16 $${Find}\:\:{U}_{{x}} \:,\:\:{U}_{{xy}\:} \:,\:\:{U}_{{yy}} \:\: \\ $$$${Given}\:{that}\::\:\: \\ $$$${U}\:=\:{x}^{\mathrm{3}} {y}\:−\:{siny} \\ $$ Commented by prakash jain last…
Question Number 7887 by tawakalitu last updated on 23/Sep/16 $${Find}\:{the}\:{first}\:{four}\:{terms}\:{of}\:{the}\:{power}\:{series}\: \\ $$$${expansion}\:{of}\:\:\:\:\:\frac{{sinx}}{\mathrm{1}\:−\:{x}}\:\:\: \\ $$ Answered by sandy_suhendra last updated on 23/Sep/16 $${from}\:{the}\:{power}\:{series}\:: \\ $$$${sin}\:{x}\:=\:\underset{{n}=\mathrm{0}} {\overset{\infty}…
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Question Number 7701 by z last updated on 10/Sep/16 $$\left({x}−\mathrm{2}{y}\right. \\ $$$$ \\ $$ Commented by Rohit 57 last updated on 11/Sep/16 $${what}\:{mean}\:{this}\:{qvestion}\:{plzzz}\: \\ $$…
Question Number 7702 by Rasheed Soomro last updated on 10/Sep/16 Commented by Rasheed Soomro last updated on 11/Sep/16 $${Given} \\ $$$${AB}={BD}={DF} \\ $$$$\angle{FGH}=\alpha \\ $$$${GF}={r}…
Question Number 73210 by TawaTawa last updated on 08/Nov/19 Commented by mr W last updated on 09/Nov/19 $$\left(\mathrm{2}\right)\:{is}\:{not}\:{defined}.\:{no}\:{unique}\:{solution}. \\ $$ Commented by TawaTawa last updated…