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Category: Geometry

Question-73663

Question Number 73663 by ajfour last updated on 14/Nov/19 Answered by ajfour last updated on 15/Nov/19 SeeQ.73673V=2((ρ2(2ϕ)2×(ds))ρ=ssinα=ssinπ6=s2$$\:{s}=\frac{{a}\sqrt{\mathrm{3}}−{r}\left(\mathrm{1}−\mathrm{cos}\:\theta\right)}{\mathrm{cos}\:\alpha}=\frac{\mathrm{2}{a}}{\mathrm{3}}\left(\mathrm{2}+\mathrm{cos}\:\theta\right) \