Question Number 71724 by TawaTawa last updated on 19/Oct/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 6169 by sanusihammed last updated on 17/Jun/16 $${A}\:{telephone}\:{wire}\:{hangs}\:{from}\:{two}\:{points}\:{P},\:{Q}\:\:\mathrm{60}{m}\:{apart} \\ $$$${P},\:{Q}\:\:{are}\:{on}\:{the}\:{same}\:{level}\:.\:{the}\:{mid}\:{point}\:{of}\:{the}\:{telephone} \\ $$$${wire}\:{is}\:\:\mathrm{3}{m}\:\:{below}\:{the}\:{level}\:{of}\:{P},\:{Q}.\:{Assuming}\:{that}\:{it}\:{hangs}\:{in}\: \\ $$$${form}\:{of}\:{a}\:{curve}\:,\:\:{find}\:{it}\:{equation}. \\ $$$$ \\ $$$${please}\:{help}.\:{thanks}\:{for}\:{your}\:{time}. \\ $$ Answered by Yozzii…
Question Number 71698 by TawaTawa last updated on 18/Oct/19 Commented by MJS last updated on 19/Oct/19 $$\mathrm{we}\:\mathrm{had}\:\mathrm{a}\:\mathrm{similar}\:\mathrm{example}\:\mathrm{a}\:\mathrm{few}\:\mathrm{weeks}\:\mathrm{ago} \\ $$ Commented by TawaTawa last updated on…
Question Number 71693 by TawaTawa last updated on 18/Oct/19 Answered by MJS last updated on 19/Oct/19 $$\mathrm{the}\:\mathrm{discs}\:\mathrm{are}\:\mathrm{cylinders} \\ $$$${V}=\pi{r}^{\mathrm{2}} {h} \\ $$$${V}=\pi×\mathrm{1}^{\mathrm{2}} ×\mathrm{1}+\pi×\mathrm{2}^{\mathrm{2}} ×\mathrm{1}+\pi×\mathrm{3}^{\mathrm{2}} ×\mathrm{1}=\mathrm{14}\pi…
Question Number 6157 by Rasheed Soomro last updated on 16/Jun/16 Answered by Yozzii last updated on 16/Jun/16 $$\mid{BC}\mid=\mid{CD}\mid=\mid{DA}\mid=\mid{AB}\mid={x}\:{units}>\mathrm{0} \\ $$$${Form}\:{the}\:{triangle}\:\bigtriangleup{GBH}\:{where}\:\angle{GBH}=\mathrm{90}° \\ $$$${and}\angle{GHB}=\theta\:\left(\mathrm{0}<\theta<\mathrm{90}°\right).\:{Let}\:\mid{GH}\mid={r}>\mathrm{0}.\:{Since} \\ $$$${H}\:{is}\:{the}\:{centre}\:{of}\:{arc}\:{GE},\:{then}\:\mid{EH}\mid=\mid{GH}\mid={r}. \\…
Question Number 71680 by TawaTawa last updated on 18/Oct/19 Answered by mind is power last updated on 18/Oct/19 $$\mathrm{the}\:\mathrm{bige}\:\mathrm{one}\:\mathrm{is}\:\mathrm{small}\ast\mathrm{k} \\ $$$$\Rightarrow\mathrm{k}^{\mathrm{2}} =\frac{\mathrm{36}}{\mathrm{16}}=\Rightarrow\mathrm{k}=\frac{\mathrm{6}}{\mathrm{4}} \\ $$$$\mathrm{diametre}\:=\frac{\mathrm{4}}{\mathrm{6}}.\mathrm{39}=\mathrm{2}.\mathrm{13}=\mathrm{26} \\…
Question Number 71673 by TawaTawa last updated on 18/Oct/19 Commented by TawaTawa last updated on 18/Oct/19 $$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$ Answered by mind is power last…
Question Number 6132 by sanusihammed last updated on 15/Jun/16 $${Evaluate}\:{the}\:{integral}\:{of}\:… \\ $$$$ \\ $$$$\left[\left({x}−\frac{{x}^{\mathrm{3}} }{\mathrm{2}}+\frac{{x}^{\mathrm{5}} }{\mathrm{2}.\mathrm{4}}−\frac{{x}^{\mathrm{7}} }{\mathrm{2}.\mathrm{4}.\mathrm{6}}+….\right)\left(\mathrm{1}−\frac{{x}^{\mathrm{2}} }{\mathrm{2}^{\mathrm{2}} }+\frac{{x}^{\mathrm{4}} }{\mathrm{2}^{\mathrm{2}} .\mathrm{4}^{\mathrm{2}} }−\frac{{x}^{\mathrm{6}} }{\mathrm{2}^{\mathrm{2}} .\mathrm{4}^{\mathrm{2}} .\mathrm{6}^{\mathrm{2}}…
Question Number 71645 by ajfour last updated on 18/Oct/19 Commented by ajfour last updated on 18/Oct/19 $${If}\:{the}\:{three}\:{inner}\:{solid}\:{spheres} \\ $$$${have}\:{radii}\:{p},{q},{r}\:{and}\:{the}\:{same}\: \\ $$$${density}\:\rho,\:{while}\:{the}\:{outer}\:{sphere} \\ $$$${has}\:{radius}\:{R},\:{and}\:{negligible} \\ $$$${mass},\:{find}\:{how}\:{high}\:{from}\:{ground}…
Question Number 6081 by LMTV last updated on 12/Jun/16 $$\int{e}^{−{st}} \frac{{t}^{{n}} }{{n}!}{dt}=? \\ $$ Commented by Yozzii last updated on 12/Jun/16 $${Let}\:{I}\left({n}\right)=\frac{\mathrm{1}}{{n}!}\int{e}^{−{st}} {t}^{{n}} {dt}\:\:\left({n}\geqslant\mathrm{0}\right). \\…