Question Number 70592 by behi83417@gmail.com last updated on 05/Oct/19 Commented by behi83417@gmail.com last updated on 05/Oct/19 $$\mathrm{convex}\:\mathrm{ABCD},\mathrm{is}\:\mathrm{given}\:\mathrm{with}: \\ $$$$\mathrm{S}\left(\mathrm{DCE}\right)=\mathrm{9},\mathrm{S}\left(\mathrm{CBE}\right)=\mathrm{10},\mathrm{S}\left(\mathrm{BAE}\right)=\mathrm{13}\:. \\ $$$$\:\:\Rightarrow\:\mathrm{S}\left(\mathrm{ADE}\right)=? \\ $$ Answered by…
Question Number 70590 by behi83417@gmail.com last updated on 05/Oct/19 Commented by behi83417@gmail.com last updated on 05/Oct/19 $$\mathrm{convex}\:\mathrm{ABCD},\mathrm{is}\:\mathrm{given}\:\mathrm{with}: \\ $$$$\boldsymbol{\mathrm{S}}_{\mathrm{ABCD}} =\boldsymbol{\mathrm{p}}\:\:\:,\:\:\:\:\:\mathrm{AB}+\mathrm{BD}+\mathrm{DC}=\boldsymbol{\mathrm{q}}\:\:\:. \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{maximum}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{for}}:\:\boldsymbol{\mathrm{AC}},\boldsymbol{\mathrm{in}}\:\boldsymbol{\mathrm{terms}} \\ $$$$\boldsymbol{\mathrm{of}}:\:\:\boldsymbol{\mathrm{p}}\:\:\boldsymbol{\mathrm{and}}\:\:\boldsymbol{\mathrm{q}}. \\…
Question Number 70587 by behi83417@gmail.com last updated on 05/Oct/19 Commented by behi83417@gmail.com last updated on 05/Oct/19 $$\mathrm{ABCD},\mathrm{is}\:\mathrm{given}. \\ $$$$\mathrm{AB}=\boldsymbol{\mathrm{a}},\mathrm{BC}=\boldsymbol{\mathrm{b}},\mathrm{CD}=\boldsymbol{\mathrm{c}},\mathrm{DA}=\boldsymbol{\mathrm{d}},\mathrm{AC}=\boldsymbol{\mathrm{m}},\mathrm{BD}=\boldsymbol{\mathrm{n}}. \\ $$$$\boldsymbol{\mathrm{show}}\:\boldsymbol{\mathrm{that}}: \\ $$$$\:\:\:\:\:\left(\boldsymbol{\mathrm{mn}}\right)^{\mathrm{2}} =\left(\boldsymbol{\mathrm{ac}}\right)^{\mathrm{2}} +\left(\boldsymbol{\mathrm{bd}}\right)^{\mathrm{2}}…
Question Number 5051 by nhoduy last updated on 05/Apr/16 $$\mathrm{7}{x}−\mathrm{4}=\mathrm{0} \\ $$ Commented by nguyentai last updated on 05/Apr/16 $$\Leftrightarrow{x}=\mathrm{1} \\ $$ Answered by FilupSmith…
Question Number 5030 by LMTV last updated on 04/Apr/16 $${y}=\frac{\mathrm{cos}\:{x}}{\:\sqrt{\mathrm{1}+\mathrm{sin}\:{x}}} \\ $$$${y}'=? \\ $$$${y}=\mathrm{cos}^{\mathrm{2}} \:\mathrm{4}{x} \\ $$$${y}'=? \\ $$ Answered by FilupSmith last updated on…
Question Number 5022 by love math last updated on 03/Apr/16 $$\frac{{n}^{\mathrm{1}.\mathrm{2}} −\mathrm{3}\sqrt{\mathrm{3}}}{{n}^{\mathrm{0}.\mathrm{8}} −\sqrt{\mathrm{3}{n}^{\mathrm{0}.\mathrm{8}} }+\mathrm{3}}−\sqrt{\mathrm{3}}\left(\sqrt{\mathrm{3}{n}^{\mathrm{0}.\mathrm{8}} }−\mathrm{1}\right) \\ $$$$ \\ $$$${Simplify} \\ $$ Commented by prakash jain…
Question Number 5017 by anujkumar last updated on 02/Apr/16 $${test} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 70516 by TawaTawa last updated on 05/Oct/19 Commented by TawaTawa last updated on 05/Oct/19 ABCD and DEFK are squares DK=6cm A(BEK)=? Answered by mr W last updated on 05/Oct/19…
Question Number 70519 by TawaTawa last updated on 05/Oct/19 Commented by mr W last updated on 05/Oct/19 $${B}+{D}=\mathrm{180}° \\ $$$$\frac{{B}}{{D}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$${B}+\frac{\mathrm{3}}{\mathrm{2}}{B}=\mathrm{180} \\ $$$$\frac{\mathrm{5}}{\mathrm{2}}{B}=\mathrm{180} \\…
Question Number 4971 by Rasheed Soomro last updated on 28/Mar/16 Commented by Rasheed Soomro last updated on 28/Mar/16 $${Write}\:{process}\:{also}. \\ $$ Commented by Rasheed Soomro…