Category: Geometry

Question Number 6217 by Rasheed Soomro last updated on 18/Jun/16 Commented by Rasheed Soomro last updated on 22/Jun/16 $$\mid FJ\mid =?$$ Commented by sandy_suhendra last…

Question Number 6169 by sanusihammed last updated on 17/Jun/16 $$AtelephonewirehangsfromtwopointsP,Q60mapart$$$$P,Qareonthesamelevel.themidpointofthetelephone$$$$wireis3mbelowthelevelofP,Q.Assumingthatithangsin$$$$formofacurve,finditequation.$$$$$$$$pleasehelp.thanksforyourtime.$$ Answered by Yozzii…

Question Number 71693 by TawaTawa last updated on 18/Oct/19 Answered by MJS last updated on 19/Oct/19 $$\mathrm{the}\mathrm{discs}\mathrm{are}\mathrm{cylinders}$$$$V=\pi r^{2}h$$$${V}=\pi×\mathrm{1}^{\mathrm{2}} ×\mathrm{1}+\pi×\mathrm{2}^{\mathrm{2}} ×\mathrm{1}+\pi×\mathrm{3}^{\mathrm{2}} ×\mathrm{1}=\mathrm{14}\pi…

Question Number 71680 by TawaTawa last updated on 18/Oct/19 Answered by mind is power last updated on 18/Oct/19 $$\mathrm{the}\mathrm{bige}\mathrm{one}\mathrm{is}\mathrm{small}\ast \mathrm{k}$$$$\Rightarrow {\mathrm{k}}^2=\frac{36}{16}=\Rightarrow \mathrm{k}=\frac{6}{4}$$$$\mathrm{diametre}\:=\frac{\mathrm{4}}{\mathrm{6}}.\mathrm{39}=\mathrm{2}.\mathrm{13}=\mathrm{26} \…

Question Number 6132 by sanusihammed last updated on 15/Jun/16 $$Evaluatetheintegralof\dots$$$$$$$$\left[\left({x}−\frac{{x}^{\mathrm{3}} }{\mathrm{2}}+\frac{{x}^{\mathrm{5}} }{\mathrm{2}.\mathrm{4}}−\frac{{x}^{\mathrm{7}} }{\mathrm{2}.\mathrm{4}.\mathrm{6}}+….\right)\left(\mathrm{1}−\frac{{x}^{\mathrm{2}} }{\mathrm{2}^{\mathrm{2}} }+\frac{{x}^{\mathrm{4}} }{\mathrm{2}^{\mathrm{2}} .\mathrm{4}^{\mathrm{2}} }−\frac{{x}^{\mathrm{6}} }{\mathrm{2}^{\mathrm{2}} .\mathrm{4}^{\mathrm{2}} .\mathrm{6}^{\mathrm{2}}…