Geometry – Page 28

Question-208782

Tinku Tara June 22, 2024 Geometry 0 Comments

Question Number 208782 by cherokeesay last updated on 22/Jun/24 Answered by mr W last updated on 23/Jun/24 Commented by cherokeesay last updated on 23/Jun/24 $${thank}\:{you}\:{master}\:!…

Question-208772

Tinku Tara June 22, 2024 Geometry 0 Comments

Question Number 208772 by Jubr last updated on 22/Jun/24 Answered by mr W last updated on 22/Jun/24 Commented by mr W last updated on 22/Jun/24…

Question-208743

Tinku Tara June 22, 2024 Geometry 0 Comments

Question Number 208743 by Tawa11 last updated on 22/Jun/24 Commented by Tawa11 last updated on 22/Jun/24 $Area of red circle .$ Commented by Tawa11 last updated on…

Question-208690

Tinku Tara June 21, 2024 Geometry 0 Comments

Question Number 208690 by Tawa11 last updated on 21/Jun/24 Answered by mr W last updated on 21/Jun/24 $(2 r - 3) \times 3 = 2^{2}$ $\Rightarrow r = \frac{13}{6}$ $s h a d e d a r e a = \frac{π}{2} {(\frac{13}{6})}^{2} - (\frac{13}{6}) \times 2 \approx 3.04$ …

Question-208639

Tinku Tara June 20, 2024 Geometry 0 Comments

Question Number 208639 by Tawa11 last updated on 20/Jun/24 Commented by mr W last updated on 20/Jun/24 $i s i t a r e d s q u a r e ?$ $d o e s o n e c o r n e r o f t h e s q u a r e l i e$ $o n t h e c e n t e r o f s e m i c i r c l e ?$ Commented…

Question-208581

Tinku Tara June 18, 2024 Geometry 0 Comments

Question Number 208581 by Tawa11 last updated on 18/Jun/24 Commented by mr W last updated on 18/Jun/24 Commented by Tawa11 last updated on 18/Jun/24 $$\mathrm{Thanks}\:\mathrm{sir}.…

Question-208493

Tinku Tara June 17, 2024 Geometry 0 Comments

Question Number 208493 by Tawa11 last updated on 17/Jun/24 Answered by A5T last updated on 17/Jun/24 $a (3 a) = x^{2} \Rightarrow x = a \sqrt{3}$ ${(4 a)}^{2} = 2 {(a \sqrt{3} + y)}^{2} = 16 a^{2} \Rightarrow r = y = 2 a \sqrt{2} - a \sqrt{3}$ $$\Rightarrow{r}={y}={a}\left(\mathrm{2}\sqrt{\mathrm{2}}−\sqrt{\mathrm{3}}\right)…

Question-208468

Tinku Tara June 16, 2024 Geometry 0 Comments

Question Number 208468 by Tawa11 last updated on 16/Jun/24 Answered by A5T last updated on 17/Jun/24 $\frac{O D \times O C}{A O \times O B} = \frac{1}{k^{2}} = \frac{9}{25} \Rightarrow k = \frac{5}{3}$ $\frac{A B}{D C} = \frac{5}{3}; A B = 5 x, D C = 3 x$ $[A B C D] = \frac{(8 x) h}{2} = 4 x h$ $$\left[{OBC}\right]=\left[{OAD}\right]=\frac{\mathrm{5}{xh}}{\mathrm{2}}−\mathrm{25}=\frac{\mathrm{3}{xh}}{\mathrm{2}}−\mathrm{9}\Rightarrow{xh}=\mathrm{16} \…

Question-208466

Tinku Tara June 16, 2024 Geometry 0 Comments

Question Number 208466 by Tawa11 last updated on 16/Jun/24 Answered by A5T last updated on 17/Jun/24 Commented by A5T last updated on 17/Jun/24 $$\mathrm{4}{x}+\mathrm{3}{x}+\mathrm{2}{x}=\mathrm{180}\Rightarrow{x}=\mathrm{20}° \…

Question-208465

Tinku Tara June 16, 2024 Geometry 0 Comments

Question Number 208465 by Tawa11 last updated on 16/Jun/24 Answered by A5T last updated on 17/Jun/24 $\frac{3 \sqrt{2}}{s} = \frac{3 \sqrt{5}}{10} \Rightarrow s = \frac{10 \sqrt{10}}{5} = 2 \sqrt{10} \Rightarrow s^{2} = 40$ Commented by Tawa11 last updated…

Category: Geometry