Question Number 204310 by BaliramKumar last updated on 12/Feb/24 Answered by mr W last updated on 12/Feb/24 Commented by mr W last updated on 12/Feb/24…
Question Number 204197 by ajfour last updated on 08/Feb/24 Answered by mr W last updated on 08/Feb/24 $$\mathrm{sin}\:\frac{\theta}{\mathrm{2}}=\frac{{a}}{{R}−{a}} \\ $$$${OC}={OB}+{BC} \\ $$$$\frac{{R}}{\mathrm{cos}\:\theta}=\sqrt{\left({R}+\mathrm{1}\right)^{\mathrm{2}} −\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{tan}\:\left(\frac{\frac{\pi}{\mathrm{2}}−\theta}{\mathrm{2}}\right)} \\…
Question Number 204171 by cherokeesay last updated on 07/Feb/24 Commented by AST last updated on 07/Feb/24 $${Are}\:{those}\:{points}\:{on}\:{the}\:{circle}\:{the}\:{vertices}\:{of}\:{a} \\ $$$${regular}\:{hexagon}?\:{Is}\:{H}\:{the}\:{midpoint}\:{of}\:\Gamma\:{and}\:{A}? \\ $$ Answered by AST last…
Question Number 203969 by mr W last updated on 03/Feb/24 Answered by Rasheed.Sindhi last updated on 03/Feb/24 $$?={x} \\ $$$$\bigtriangleup\mathrm{ABC}\sim\bigtriangleup\mathrm{ADE} \\ $$$$\frac{\mathrm{3}}{{r}}=\frac{\mathrm{4}}{\mathrm{4}−{r}}=\frac{\mathrm{5}}{{x}+{r}}\Rightarrow\mathrm{4}{r}=\mathrm{12}−\mathrm{3}{r}\Rightarrow{r}=\frac{\mathrm{12}}{\mathrm{7}} \\ $$$$\frac{\mathrm{3}}{{r}}=\frac{\mathrm{5}}{{x}+{r}}\Rightarrow\frac{\mathrm{3}}{\frac{\mathrm{12}}{\mathrm{7}}}=\frac{\mathrm{5}}{{x}+\frac{\mathrm{12}}{\mathrm{7}}} \\…
Question Number 203803 by ajfour last updated on 28/Jan/24 Answered by ajfour last updated on 28/Jan/24 $$\mathrm{2}{s}^{\mathrm{2}} =\left({b}^{\mathrm{2}} +{c}^{\mathrm{2}} \right)−\left(\frac{{h}−{k}}{{h}+{k}}\right)\left({b}^{\mathrm{2}} −{c}^{\mathrm{2}} \right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:−\frac{\mathrm{2}{hk}}{\left({h}+{k}\right)^{\mathrm{2}} }\left({a}^{\mathrm{2}}…
Question Number 203778 by mr W last updated on 27/Jan/24 Answered by mr W last updated on 27/Jan/24 Commented by mr W last updated on…
Question Number 203613 by mr W last updated on 23/Jan/24 Commented by mr W last updated on 23/Jan/24 $${find}\:\frac{{R}}{{r}}=? \\ $$ Commented by esmaeil last…
Question Number 203569 by cherokeesay last updated on 22/Jan/24 Commented by a.lgnaoui last updated on 22/Jan/24 $$\mathrm{2}\left(\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{d}\right)=\mathrm{360} \\ $$$$\:\:\left(\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{d}\right)=\mathrm{180} \\ $$$$\:\:\left(\mathrm{a}+\mathrm{b}\right)=\mathrm{180}−\left(\mathrm{c}+\mathrm{d}\right) \\ $$$$ \\ $$$$\:\:\:\:\mathrm{tan}\:\left(\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{b}}\right)=−\mathrm{tan}\:\left(\boldsymbol{\mathrm{c}}+\boldsymbol{\mathrm{d}}\right)…
Question Number 203602 by mr W last updated on 22/Jan/24 Answered by mr W last updated on 23/Jan/24 Commented by mr W last updated on…
Question Number 203557 by ajfour last updated on 21/Jan/24 Commented by ajfour last updated on 21/Jan/24 $${Find}\:{maimum}\:{blue}\:{shaded}\:{area}. \\ $$ Answered by mr W last updated…