Category: Geometry

Question Number 71255 by ajfour last updated on 13/Oct/19 Commented by MJS last updated on 13/Oct/19 $$\mathrm{the}\mathrm{maximum}\mathrm{area}\mathrm{depends}\mathrm{on}a$$$$\mathrm{the}\mathrm{area}\mathrm{for}\theta =90°\mathrm{is}\frac{\pi }{4}b\mathrm{and}\mathrm{this}\mathrm{value}\mathrm{is}$$$$\mathrm{again}\mathrm{reached}\mathrm{st}\theta =45°.\mathrm{this}\mathrm{is}\mathrm{only}\mathrm{possible}$$$$\mathrm{if}a=\sqrt{2}b\mathrm{at}\mathrm{least}.\mathrm{for}b⩽a⩽\sqrt{2}b\mathrm{the}\mathrm{maximum}$$$$\mathrm{area}\:\mathrm{is}\:\frac{\pi}{\mathrm{4}}{b};\:\mathrm{for}\:{a}>\sqrt{\mathrm{2}}{b}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{is}\:\mathrm{at}\:{r}={a}…

Question Number 5695 by FilupSmith last updated on 24/May/16 Commented by FilupSmith last updated on 24/May/16 $$\mathrm{What}\mathrm{kinds}\mathrm{of}\mathrm{methods}\mathrm{can}\mathrm{be}\mathrm{used}$$$$\mathrm{to}\mathrm{find}\mathrm{the}\mathrm{area}\mathrm{of}ABC?$$$$\left(\mathrm{Both}\mathrm{circles}\mathrm{are}\mathrm{identical}\right)$$ Commented by…

Question Number 71184 by ajfour last updated on 12/Oct/19 Commented by ajfour last updated on 12/Oct/19 $$Eachsemicirclehaveradius$$$$unity.Findmaximumvalueofx.$$ Commented by ajfour last…

Question Number 5626 by Rasheed Soomro last updated on 23/May/16 $$\mathrm{What}\mathrm{is}\mathrm{the}\mathbf{length}\mathbf{of}\mathbf{chord}\mathrm{in}\mathrm{a}\mathbf{circle}\mathbf{of}$$$$\mathbf{radius}\mathbf{r}\mathrm{which}\mathrm{divides}\mathrm{the}\mathbf{circumference}\mathbf{of}\mathbf{circle}\mathrm{in}\mathbf{m}:\mathbf{n}?$$ Answered by mrW last updated on 17/Nov/16 $$\theta =2\pi \cdot \frac{m}{m+n}$$$${L}=\mathrm{2}\centerdot{r}\centerdot\mathrm{sin}\:\left(\theta/\mathrm{2}\right)=\mathrm{2}\centerdot{r}\centerdot\mathrm{sin}\:\left(\frac{{m}\pi}{{m}+{n}}\right)…

Question Number 5620 by sanusihammed last updated on 22/May/16 $$Findtheresolvedpartofthevectora=6i-3j+9k$$$$inthediectionofb=2i+2j-k$$$$$$$$pleasehelp.$$$$$$$$igottheanswertobe(-1)$$ Commented by prakash…