Category: Geometry

Question Number 71428 by TawaTawa last updated on 15/Oct/19 Answered by ajfour last updated on 15/Oct/19 Commented by ajfour last updated on 15/Oct/19 $${P}\:\left[{r}\mathrm{cos}\:\left(\theta−\phi\right),\:{r}\mathrm{sin}\:\left(\theta−\phi\right)\right] \…

Question Number 71410 by TawaTawa last updated on 15/Oct/19 Answered by MJS last updated on 15/Oct/19 $$A=\left(\begin{array}{c}0\\ 0\end{array}\right)B=\left(\begin{array}{c}p\\ 0\end{array}\right)C=\left(\begin{array}{c}p\\ q\end{array}\right)D=\left(\begin{array}{c}0\\ q\end{array}\right)$$$$DC:y=q$$$$AC:y=\frac{q}{p}x$$$${BE}:\:{y}=−\frac{{p}}{{q}}{x}+\frac{{p}^{\mathrm{2}} }{{q}} \…

Question Number 5822 by Rasheed Soomro last updated on 30/May/16 $$\mathcal{P}rovethatamongall\mathit{t}\mathit{r}\mathit{i}\mathit{a}\mathit{n}\mathit{g}\mathit{l}\mathit{e}\mathit{s},$$$$whichhavesame\mathit{c}\mathit{i}\mathit{r}\mathit{c}\mathit{u}\mathit{m}-\mathit{r}\mathit{a}\mathit{d}\mathit{i}\mathit{u}\mathit{s},$$$$the\mathit{e}\mathit{q}\mathit{u}\mathit{i}\mathit{l}\mathit{a}\mathit{t}\mathit{e}\mathit{r}\mathit{a}\mathit{l}\mathit{t}\mathit{r}\mathit{i}\mathit{a}\mathit{n}\mathit{g}\mathit{l}\mathit{e}has$$$$\mathit{m}\mathit{a}\mathit{x}\mathit{i}\mathit{m}\mathit{u}\mathit{m}\mathit{a}\mathit{r}\mathit{e}\mathit{a}.$$ Terms of Service Privacy Policy Contact:…

Question Number 5763 by sanusihammed last updated on 26/May/16 $$Thanks.pleasecanyoushowmetherestsolution.iwantto$$$$seethelaststeps.2^x=4x.Thanksforthetimeandthe$$$$previoussolution.$$ Commented by nburiburu last updated on 25/Jun/16 $${graph}\:{the}\:{functions}\:{y}=\mathrm{2}^{{x}}…

Question Number 71255 by ajfour last updated on 13/Oct/19 Commented by MJS last updated on 13/Oct/19 $$\mathrm{the}\mathrm{maximum}\mathrm{area}\mathrm{depends}\mathrm{on}a$$$$\mathrm{the}\mathrm{area}\mathrm{for}\theta =90°\mathrm{is}\frac{\pi }{4}b\mathrm{and}\mathrm{this}\mathrm{value}\mathrm{is}$$$$\mathrm{again}\mathrm{reached}\mathrm{st}\theta =45°.\mathrm{this}\mathrm{is}\mathrm{only}\mathrm{possible}$$$$\mathrm{if}a=\sqrt{2}b\mathrm{at}\mathrm{least}.\mathrm{for}b⩽a⩽\sqrt{2}b\mathrm{the}\mathrm{maximum}$$$$\mathrm{area}\:\mathrm{is}\:\frac{\pi}{\mathrm{4}}{b};\:\mathrm{for}\:{a}>\sqrt{\mathrm{2}}{b}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{is}\:\mathrm{at}\:{r}={a}…