Geometry – Page 293

Question-68941

Tinku Tara June 3, 2023 Geometry 0 Comments

Question Number 68941 by ahmadshah last updated on 17/Sep/19 Commented by mr W last updated on 17/Sep/19 $w h a t i f t h e c a b l e i s 100 m l o n g ?$ Commented by MJS last updated…

In-the-figure-we-have-7-circles-having-the-same-radius-Determine-the-ratio-between-the-perimeter-of-one-of-the-circle-and-the-perimeter-of-the-gray-region-

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Question Number 68930 by Maclaurin Stickker last updated on 17/Sep/19 $In the figure we have 7 circles having$ $the same radius . Determine the ratio$ $between the perimeter of one of the$ $circle and the perimeter of the gray region .$ Commented by Maclaurin Stickker last updated…

In-a-cube-ABCD-EFGH-with-a-side-length-of-4-cm-Point-Q-is-the-middle-of-line-AE-and-point-P-lies-on-the-extension-of-line-AB-so-that-BP-AB-1-2-If-is-the-angle-between-the-QG-line-and-the-PQH

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Question Number 134428 by liberty last updated on 03/Mar/21 $In a cube ABCD . EFGH with a$ $side length of 4 cm . Point Q is the$ $middle of line AE and point P$ $lies on the extension of line AB$ $so that BP : AB = 1 : 2 . If θ is the$ $angle between the QG line and$ $the PQH plane, then \sin θ = ?$ Answered…

Prove-that-the-regular-pentagon-is-possible-with-ruler-and-compass-

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Question Number 3348 by RasheedSindhi last updated on 11/Dec/15 $P r o v e t h a t t h e r e g u l a r p e n t a g o n$ $i s p o s s i b l e w i t h r u l e r a n d c o m p a s s .$ Commented by Rasheed Soomro last updated on 11/Dec/15 $H o w c a n w e p r o v e t h a t a n g l e 108 ° i s$ $${possible}?…

Question-134396

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Question Number 134396 by I want to learn more last updated on 03/Mar/21 Commented by mr W last updated on 03/Mar/21 $P + Q = 2 \times 10 \times \sin \frac{75 °}{2} = 12.2 u n i t$ Commented…

Bring-up-the-topic-challenge-started-by-Filup-at-the-top-Shall-we-start-new-topic-at-the-beginning-of-calendar-month-See-older-post-dt-24-11-by-Filup-

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Question Number 3304 by prakash jain last updated on 09/Dec/15 $Bring up the topic / challenge started by Filup at the top .$ $Shall we start new topic at the beginning$ $of calendar month ?$ $See older post dt 24.11 by Filup$ Commented by Filup last updated on…

The-square-ABCD-has-side-equal-to-1-and-the-distance-AP-is-1-8-Calculate-the-side-of-the-equilateral-triangle-PMN-inscribed-in-the-square-

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Question Number 68831 by Maclaurin Stickker last updated on 15/Sep/19 $The square A B C D has side equal to 1$ $and the distance A P is \frac{1}{8} .$ $Calculate the side of the equilateral$ $triangle P M N inscribed in the square .$ Commented by Maclaurin Stickker last updated…

For-a-triangle-with-perpandicular-height-h-and-base-length-b-the-area-of-the-triangle-is-given-by-A-1-2-hb-Why-is-this-the-case-I-understand-that-two-identicle-triangles-can-construct-a-rectangl

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Question Number 3280 by Filup last updated on 09/Dec/15 $For a triangle with perpandicular$ $height h and base length b, the$ $area of the triangle is given by :$ $A = \frac{1}{2} h b$ $Why is this the case ?$ $I understand that two identicle triangles$ $$\mathrm{can}\:\mathrm{construct}\:\mathrm{a}\:{rectangle},\:\mathrm{so}\:\mathrm{the}\:\mathrm{area} \…

Could-3-2-be-drawn-on-numbered-line-with-the-help-of-ruler-and-compass-only-

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Question Number 3262 by Rasheed Soomro last updated on 08/Dec/15 $C o u l d^{3} \sqrt{2} b e d r a w n o n n u m b e r e d l i n e w i t h$ $t h e h e l p o f r u l e r a n d c o m p a s s o n l y ?$ Commented by prakash jain last updated on 09/Dec/15 $$\sqrt[{\mathrm{3}}]{\mathrm{2}}\:\mathrm{cannot}\:\mathrm{be}\:\mathrm{drawn}\:\mathrm{using}\:\mathrm{a}\:\mathrm{ruler}\:\mathrm{and}\:\mathrm{compass}.…

How-could-5-be-drawn-on-numbered-line-using-scale-and-compass-only-Exactly-5-not-its-decimal-approximation-

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Question Number 3249 by Rasheed Soomro last updated on 08/Dec/15 $H o w c o u l d \sqrt{5} b e d r a w n o n n u m b e r e d l i n e u s i n g$ $s c a l e a n d c o m p a s s o n l y ? (E x a c t l y \sqrt{5} n o t i t s d e c i m a l a p p r o x i m a t i o n .)$ Answered by prakash jain last updated on 08/Dec/15 $$\mathrm{For}\:\sqrt{\mathrm{5}} \…

Category: Geometry