Category: Geometry

Question Number 67977 by behi83417@gmail.com last updated on 02/Sep/19 Commented by behi83417@gmail.com last updated on 02/Sep/19 $$\mathbf{AD}=\mathbf{DC},\mathrm{\angle }\mathbf{AEB}={90}^{\bullet }.$$$$\mathbf{find}:\mathbf{ED}\mathbf{in}\mathbf{terms}\mathbf{of}:\mathbf{a},\mathbf{b},\mathbf{c}.$$ Answered by $@ty@m123…

Question Number 67969 by behi83417@gmail.com last updated on 02/Sep/19 $$\mathbf{Two}\mathbf{triangles}{△}_1\mathbf{and}{△}_2\mathbf{are}\mathbf{given},\mathbf{such}$$$$\mathbf{that}\mathbf{length}\mathbf{of}\mathbf{sides}\mathbf{of}\mathbf{triangle}1,\mathbf{are}$$$$\mathbf{equail}\mathbf{to}\mathbf{length}\mathbf{of}\mathbf{medians}\mathbf{of}\mathbf{triangle}2.$$$$1.\mathbf{find}\mathbf{the}\mathbf{ratio}\mathbf{of}\mathbf{areas}\mathbf{of}\mathbf{triangles}.$$$$2.\mathbf{given}\mathbf{that}\mathbf{small}\mathbf{side}\mathbf{of}{△}_1,\mathbf{be}\mathbf{equail}\mathbf{to}:\sqrt{2}$$$$\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{one}}\:\boldsymbol{\mathrm{angle}}\:\boldsymbol{\mathrm{be}}:\mathrm{90}^{\bullet} . \…

Question Number 67860 by TawaTawa last updated on 01/Sep/19 Commented by TawaTawa last updated on 01/Sep/19 $$\mathrm{Find}\mathrm{angle}\mathrm{a}$$ Commented by mr W last updated…

Question Number 67852 by mr W last updated on 01/Sep/19 Commented by Prithwish sen last updated on 01/Sep/19 $$$$$$\mathbf{A}=(0,\mathbf{a}),\mathbf{B}=(\frac{-4}{\mathbf{a}},0),\mathbf{C}=(\frac{20}{\mathbf{a}},-9\mathbf{a}),\mathbf{D}=(\frac{2}{\mathbf{a}},0)$$$$\mathbf{E}=(0,\frac{-3\mathbf{a}}{2})$$$$\mathrm{Equation}\:\mathrm{of}\:\mathrm{line}\:\mathrm{passing}\:\mathrm{through}\:\mathrm{A}\:\mathrm{and}\:\mathrm{D}…

Question Number 133371 by I want to learn more last updated on 21/Feb/21 Answered by mr W last updated on 22/Feb/21 Commented by mr W…