Category: Geometry

Question Number 67774 by TawaTawa last updated on 31/Aug/19 Answered by MJS last updated on 31/Aug/19 $$DE=AB=2r$$$$\mathrm{area}\mathrm{of}\mathrm{semicircle}=\frac{\pi }{2}{r}^2$$$$\mathrm{area}\mathrm{of}\mathrm{triangle}=\frac{1}{2}\mid AB\mid h=rh$$$$\mathrm{with}h=r\tan x$$$$\:\:\:\:\:={r}^{\mathrm{2}}…

Question Number 67775 by TawaTawa last updated on 31/Aug/19 Answered by MJS last updated on 31/Aug/19 $$ABCD\mathrm{is}\mathrm{a}\mathrm{square}\mathrm{with}\mathrm{side}s=\sqrt{196}=14$$$$\Rightarrow \mathrm{the}\mathrm{yellow}{\mathrm{sector}}^{\prime }\mathrm{s}\mathrm{area}=\frac{\pi }{8}{s}^2=\frac{49\pi }{2}\mathrm{minus}$$$$\mathrm{the}\mathrm{white}\mathrm{segment}\mathrm{which}\mathrm{intersects}\mathrm{the}$$$$\mathrm{diagonal}\:\mathrm{in}\:\mathrm{the}\:\mathrm{center}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square} \…

Question Number 67749 by TawaTawa last updated on 31/Aug/19 Answered by JDamian last updated on 31/Aug/19 $$AssumingA,BandCpointsarethecenters$$$$oftheircircles:$$$$$$$${AC}={R}_{{A}} −{R}_{{C}} =\mathrm{11}−\mathrm{5}=\mathrm{6}…

Question Number 67728 by TawaTawa last updated on 30/Aug/19 Commented by mr W last updated on 30/Aug/19 $$questionisnotclear.$$$$is\mathrm{\angle }BAD=90°asmarkedoris$$$$\mathrm{\angle }BAC=90°asshown?$$ Commented…

Question Number 67692 by mr W last updated on 30/Aug/19 Answered by mr W last updated on 30/Aug/19 Commented by mr W last updated on…