Geometry – Page 301

Question-67026

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Question Number 67026 by TawaTawa last updated on 21/Aug/19 Commented by Tony Lin last updated on 22/Aug/19 $∵ s l o p e o f L_{B C} = t a n 150 ° = - \frac{\sqrt{3}}{3}$ $∴ L_{B C} : y = - \frac{\sqrt{3}}{3} (x + 4)$ $$\because{L}_{{BC}} \bot{L}_{{AB}}…

Consider-quadrilateral-ABCD-same-as-in-Q-1378-with-same-conditions-restrictions-Pl-refer-the-Question-again-What-could-be-possible-minimum-and-maximum-area-of-the-quadrila

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Question Number 1395 by Rasheed Soomro last updated on 28/Jul/15 $C o n s i d e r quadrilateral ABCD s a m e a s i n Q 1378 w i t h$ $s a m e c o n d i t i o n s / r e s t r i c t i o n s (P l r e f e r t h e Q u e s t i o n a g a i n) .$ $∙ W h a t c o u l d b e p o s s i b l e minimum a n d maximum area$ $o f t h e q u a d r i l a t e r a l ?$ $∙ W h e n q u s d r i l a t e r a l h a s minimum area w h a t i s t h e v a l u e / s$ $o f m ∠ A ? S i m i l a r l y w h a t i s v a l u e / s o f m ∠ A i n c a s e o f$ $maximum area ?$ $$…

Q-is-there-any-angle-in-a-circle-

Tinku Tara June 3, 2023 Geometry 0 Comments

Question Number 1387 by navajyoti.tamuli.tamuli@gmail. last updated on 27/Jul/15 $Q . i s t h e r e a n y a n g l e i n a c i r c l e ?$ Commented by Rasheed Soomro last updated on 28/Jul/15 $T w o a n s w e r s c a n b e g i v e n . E a c h h a s i t s o w n r e a s o n i n g .$ $(i) T h e r e a r e i n f i n i t y n u m b e r o f a n g l e s .$ $${Consider}\:{a}\:{polygon}\:{of}\:{n}\:{angles}\:{inscribed}\:{in}\:{a}\:{circle}:…

Four-sides-mAB-mBC-mCD-and-mDA-of-a-quadrilateral-ABCD-have-measurement-a-b-c-and-d-units-respectively-Let-the-sum-of-any-adjacent-sides-is-not-equal-to-the

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Question Number 1378 by Rasheed Soomro last updated on 28/Jul/15 $F o u r s i d e s m \overset{―}{AB}, m \overset{―}{BC}, m \overset{―}{CD} a n d m \overset{―}{DA} o f a quadrilateral$ $ABCD h a v e m e a s u r e m e n t a, b, c a n d d u n i t s r e s p e c t i v e l y .$ $L e t t h e s u m o f a n y a d j a c e n t s i d e s i s n o t e q u a l t o t h e s u m o f$ $r e m a i n i n g a d j a c e n t s i d e s a n d m e a s u r e m e n t o f a l l t h e s i d e s$ $i s p o s i t i v e a n d r e a l .$ $$\:\:\:\:\:\:{What}\:{could}\:{be}\:{the}\:{possible}\:{minimum}\:{and}\:{maximum}\:{values}…

3-log-3x-4-4-log-4x-3-

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Question Number 1343 by Rasheed Soomro last updated on 24/Jul/15 $3^{l o g 3 x + 4} = 4^{l o g 4 x + 3}$ Answered by 112358 last updated on 24/Jul/15 $T a k i n g l o g s t o b a s e e o n b o t h s i d e s$ $$\Rightarrow\left({log}\mathrm{3}{x}+\mathrm{4}\right){ln}\mathrm{3}=\left({log}\mathrm{4}{x}+\mathrm{3}\right){ln}\mathrm{4} \…

Question-132373

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Question Number 132373 by Ari last updated on 13/Feb/21 Answered by Ari last updated on 13/Feb/21 Answered by mr W last updated on 14/Feb/21 Commented…

If-3-log-3x-4-log-4x-find-x-

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Question Number 1304 by 314159 last updated on 20/Jul/15 $I f 3^{l o g 3 x} = 4^{l o g 4 x}, f i n d x .$ Answered by Rasheed Soomro last updated on 20/Jul/15 $$\mathrm{3}^{{log}\:\mathrm{3}{x}}…

Prove-that-AM-gt-HM-

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Question Number 1268 by 314159 last updated on 18/Jul/15 $Prove that AM > HM .$ Answered by prakash jain last updated on 18/Jul/15 $AM = \frac{a + b}{2}, HM = \frac{2 a b}{a + b}$ $$\mathrm{AM}−\mathrm{HM}=\frac{{a}+{b}}{\mathrm{2}}−\frac{\mathrm{2}{ab}}{{a}+{b}}=\:\frac{\left({a}−{b}\right)^{\mathrm{2}} }{\mathrm{2}\left({a}+{b}\right)} \…

If-the-line-x-1-2-y-1-3-z-1-4-x-3-1-y-k-2-z-1-intersect-the-value-of-k-is-

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Question Number 132327 by liberty last updated on 13/Feb/21 $If the line {\begin{cases} \frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 1}{4} \\ \frac{x - 3}{1} = \frac{y - k}{2} = \frac{z}{1} \end{cases}$ $intersect . the value of k is$ Answered by Ar Brandon last updated on 13/Feb/21 $$\mathrm{L}_{\mathrm{1}} :\:\mathrm{i}−\mathrm{j}+\mathrm{k}+\lambda\left(\mathrm{2i}+\mathrm{3j}+\mathrm{4k}\right)=\left(\mathrm{1}+\mathrm{2}\lambda\right)\mathrm{i}+\left(\mathrm{3}\lambda−\mathrm{1}\right)\mathrm{j}+\left(\mathrm{4}\lambda+\mathrm{1}\right)\mathrm{k} \…

show-that-tan-1-1-x-2-1-x-1-2-tan-1-x-

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Question Number 1157 by navajyoti.tamuli.tamuli@gmail. last updated on 06/Jul/15 $s h o w t h a t$ ${t a n}^{- 1} (\frac{\sqrt{1 + x^{2}} - 1}{x}) = \frac{1}{2} {t a n}^{- 1} x$ Answered by prakash jain last updated…

Category: Geometry