Question Number 197970 by mr W last updated on 06/Oct/23 Answered by Frix last updated on 07/Oct/23 $${r}_{\mathrm{1}} =\mathrm{4} \\ $$$${r}_{\mathrm{2}} =\mathrm{2} \\ $$$${r}_{\mathrm{3}} =\mathrm{1}…
Question Number 197920 by cortano12 last updated on 04/Oct/23 Commented by cortano12 last updated on 04/Oct/23 $$\mathrm{if}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{shaded}\:\mathrm{is}\:\mathrm{320}\:\mathrm{cm}^{\mathrm{2}} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{big}\:\mathrm{triangle}.\: \\ $$ Answered by Tokugami last…
Question Number 197680 by mr W last updated on 26/Sep/23 Commented by mr W last updated on 26/Sep/23 $${unsolved}\:{old}\:{question}\:{Q}#\mathrm{197245} \\ $$ Answered by mr W…
Question Number 197670 by mr W last updated on 26/Sep/23 Commented by mr W last updated on 26/Sep/23 $${unsolved}\:{old}\:{question}\:{Q}#\mathrm{197017} \\ $$ Commented by ajfour last…
Question Number 197644 by gungun last updated on 25/Sep/23 Commented by gungun last updated on 25/Sep/23 $${find}\:{the}\:{pink}\:{area} \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 197636 by universe last updated on 25/Sep/23 Answered by mr W last updated on 25/Sep/23 $${s}={x}+{y} \\ $$$$\left({x}+\mathrm{3}\right)^{\mathrm{2}} +{y}^{\mathrm{2}} =\left(\mathrm{8}\sqrt{\mathrm{2}}\right)^{\mathrm{2}} \\ $$$$\left({x}+\mathrm{3}\right)^{\mathrm{2}} +\left({s}−{x}\right)^{\mathrm{2}}…
Question Number 197595 by universe last updated on 23/Sep/23 Commented by universe last updated on 23/Sep/23 $$\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{equilateral}\:\mathrm{triangle}\:? \\ $$ Answered by MM42 last updated on…
Question Number 197582 by cherokeesay last updated on 22/Sep/23 Answered by som(math1967) last updated on 23/Sep/23 Commented by som(math1967) last updated on 23/Sep/23 $${let}\:{rad}\:{of}\:{big}\:{semicircle}={R} \\…
Question Number 197541 by a.lgnaoui last updated on 20/Sep/23 $$\boldsymbol{\mathrm{Montrer}}\:\boldsymbol{\mathrm{que}} \\ $$$$\:\:\:\:\:\boldsymbol{\mathrm{x}}=\frac{\boldsymbol{\mathrm{an}}+\boldsymbol{\mathrm{bm}}}{\boldsymbol{\mathrm{m}}+\boldsymbol{\mathrm{n}}} \\ $$ Commented by a.lgnaoui last updated on 20/Sep/23 Commented by a.lgnaoui last…
Question Number 197499 by cherokeesay last updated on 19/Sep/23 Answered by HeferH last updated on 19/Sep/23 $$\: \\ $$$$\:\frac{{x}}{{r}}\:=\:\frac{\mathrm{4}{r}}{\mathrm{5}{r}}\:\:\Rightarrow\:{x}\:=\:\frac{\mathrm{4}{r}}{\mathrm{5}}\: \\ $$$$\:{Green}\:=\:{Sqr}/\mathrm{2}\:−\:\frac{\mathrm{4}{r}}{\mathrm{5}}\:\centerdot\:\mathrm{4}{r}\:\centerdot\frac{\mathrm{1}}{\mathrm{2}}\: \\ $$$$\:{Green}\:=\:\frac{\mathrm{16}{r}^{\mathrm{2}} }{\mathrm{2}}\:−\frac{\mathrm{16}{r}^{\mathrm{2}} }{\mathrm{10}}\:=\:\frac{\mathrm{4}\centerdot\mathrm{16}{r}^{\mathrm{2}}…