Question Number 201808 by ahmetgg last updated on 12/Dec/23 Commented by ahmetgg last updated on 12/Dec/23 Syhthetic solution please. Answered by mr W last updated on 12/Dec/23…
Question Number 201707 by ajfour last updated on 10/Dec/23 Answered by mr W last updated on 11/Dec/23 Commented by mr W last updated on 11/Dec/23…
Question Number 201599 by mr W last updated on 09/Dec/23 Commented by AST last updated on 09/Dec/23 $${Are}\:{those}\:{numbers}\:{areas}\:{or}\:{lengths}? \\ $$ Commented by mr W last…
Question Number 201562 by Mingma last updated on 09/Dec/23 Answered by mr W last updated on 09/Dec/23 $${r}={radius}\:{of}\:{quarter}\:{circle} \\ $$$${a}={side}\:{length}\:{of}\:{square} \\ $$ Commented by mr…
Question Number 201561 by Mingma last updated on 09/Dec/23 Answered by ajfour last updated on 11/Dec/23 Commented by ajfour last updated on 11/Dec/23 $$\mathrm{2}\theta+\mathrm{2}\phi=\frac{\pi}{\mathrm{2}} \\…
Question Number 201604 by ajfour last updated on 09/Dec/23 Commented by ajfour last updated on 09/Dec/23 $${Both}\:{circles}\:{in}\:{blue}\:{have}\:{equal} \\ $$$${radii}.\:{Find}. \\ $$ Answered by mr W…
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Question Number 201322 by cherokeesay last updated on 04/Dec/23 Answered by AST last updated on 05/Dec/23 $${Let}\:\angle{EDC}=\beta\Rightarrow\angle{ABD}=\mathrm{2}\beta−\mathrm{90} \\ $$$${EC}^{\mathrm{2}} =\mathrm{2}−\mathrm{2}{cos}\beta…\left({i}\right) \\ $$$${BC}^{\mathrm{2}} ={BD}^{\mathrm{2}} +\mathrm{1}−\mathrm{2}{BD}\boldsymbol{{D}}{Ccos}\left(\mathrm{2}\beta\right)…\left({ii}\right) \\…
Question Number 201298 by ajfour last updated on 03/Dec/23 Commented by ajfour last updated on 03/Dec/23 $${Find}\:{IJ}\:\:\:{in}\:{terms}\:{of}\:{a},{b},{c}. \\ $$ Commented by mr W last updated…