Category: Geometry

Question Number 193162 by ajfour last updated on 05/Jun/23 Commented by ajfour last updated on 05/Jun/23 $${Determine}\:\:\frac{{r}}{{R}}\:\:{in}\:{terms}\:{of}\:\mathrm{0}<{m}<\mathrm{1}. \\ $$ Commented by York12 last updated on…

Question Number 65491 by mr W last updated on 30/Jul/19 Commented by mr W last updated on 30/Jul/19 $$\left[{Q}\mathrm{65312}\:{reposted}\right] \\ $$$${find}\:{x}=? \\ $$ Answered by…

Question Number 65366 by Tawa1 last updated on 29/Jul/19 Commented by Prithwish sen last updated on 29/Jul/19 $$\mathrm{the}\:\mathrm{length}\:\mathrm{is} \\ $$$$=\:\mathrm{3}\:+\:\mathrm{2}×\mathrm{2}\:+\mathrm{2}×\frac{\mathrm{2}^{\mathrm{2}} }{\mathrm{3}}\:+\:\mathrm{2}×\frac{\mathrm{2}^{\mathrm{3}} }{\mathrm{3}^{\mathrm{2}} }\:+\:\mathrm{2}×\frac{\mathrm{2}^{\mathrm{4}} }{\mathrm{3}^{\mathrm{3}} }\:+\:…….…

Question Number 65334 by Tawa1 last updated on 28/Jul/19 Answered by mr W last updated on 28/Jul/19 $$\angle{D}=\mathrm{360}−\mathrm{126}−\mathrm{42}×\mathrm{2}=\mathrm{150}° \\ $$$$\frac{{DC}}{\mathrm{sin}\:{x}}=\frac{{AC}}{\mathrm{sin}\:\mathrm{150}} \\ $$$$\Rightarrow{DC}=\frac{\mathrm{sin}\:{x}}{\mathrm{sin}\:\mathrm{150}}×{AC} \\ $$$$\frac{{AC}}{\mathrm{sin}\:\mathrm{126}}=\frac{{AB}}{\mathrm{sin}\:\left[\mathrm{42}−\left(\mathrm{30}−{x}\right)\right]}=\frac{{AB}}{\mathrm{sin}\:\left({x}+\mathrm{12}\right)} \\…

Question Number 65314 by Tony Lin last updated on 28/Jul/19 Commented by Tony Lin last updated on 28/Jul/19 $${prove}\:{that}\:\frac{\mathrm{1}}{{GM}}−\frac{\mathrm{1}}{{HM}}=\frac{\mathrm{1}}{{AM}}−\frac{\mathrm{1}}{{BM}} \\ $$ Terms of Service Privacy…