Category: Geometry

Question Number 206292 by cortano21 last updated on 11/Apr/24 Answered by A5T last updated on 11/Apr/24 $$LetAE=x;BE=y;BF=v;FC=w$$$$S+39=\frac{(2v+w)(x+y)}{2}=\frac{2v(x+y)}{2}+15\Rightarrow S=vx$$$$wx=54-S=30-yw\Rightarrow yw=S-24$$$$\frac{\left[BFD\right]}{\left[DFC\right]}=\frac{v}{w}\Rightarrow \left[BFD\right]=\frac{15v}{w}$$$$\frac{\left[{EDB}\right]}{\left[{ADE}\left[\right.\right.}=\frac{{y}}{{x}}\Rightarrow{EDB}=\frac{\mathrm{27}{y}}{{x}}…

Question Number 206269 by cortano21 last updated on 10/Apr/24 Commented by A5T last updated on 11/Apr/24 Commented by A5T last updated on 11/Apr/24 $${General}\:{formula}.\:{When}\:{k}_{\mathrm{1}} {k}_{\mathrm{2}}…

Question Number 206232 by mr W last updated on 09/Apr/24 Answered by A5T last updated on 09/Apr/24 $$S_2=S_1+S_3-2AB\times BCcos\left(\theta \right)$$$${S}_{\mathrm{1}} ={S}_{\mathrm{2}} +{S}_{\mathrm{3}}…

Question Number 206198 by lmcp1203 last updated on 09/Apr/24 Answered by A5T last updated on 09/Apr/24 $$\frac{sin4\theta }{AD}=\frac{sin(90-3\theta )}{AB};\frac{sin\left(\theta \right)}{AD}=\frac{sin(90-4\theta )}{CD=AB}$$$$\Rightarrow \frac{sin\left(4\theta \right)}{sin(90-3\theta )}=\frac{sin\left(\theta \right)}{sin(90-4\theta )}\Rightarrow x=20°$$ Answered by lmcp1203 last…

Question Number 206111 by cortano21 last updated on 07/Apr/24 Commented by cortano21 last updated on 07/Apr/24 $$$$ Answered by nikif99 last updated on…