Category: Geometry

Question Number 203401 by cherokeesay last updated on 18/Jan/24 Answered by MM42 last updated on 18/Jan/24 $$<B={30}^o$$$$AB=2\sqrt{3}\times cos30=3$$$$R=\sqrt{21}$$$$EC=2\sqrt{3}\times cos60=\sqrt{3}$$$${r}=\sqrt{\mathrm{3}}×{tan}\mathrm{30}\Rightarrow{r}=\mathrm{1}…

Question Number 203327 by mr W last updated on 16/Jan/24 Answered by ajfour last updated on 16/Jan/24 Commented by ajfour last updated on 16/Jan/24 $${What}\:{would}\:{r}\:{be}\:{in}\:{this}\:{case}?…

Question Number 203282 by mr W last updated on 14/Jan/24 Commented by cortano12 last updated on 14/Jan/24 $$\mathrm{AD}\parallel \mathrm{BC}?$$ Commented by mr W last…

Question Number 203232 by Mathstar last updated on 13/Jan/24 Answered by mr W last updated on 13/Jan/24 Commented by mr W last updated on 13/Jan/24…

Question Number 203187 by Amidip last updated on 12/Jan/24 Answered by mr W last updated on 12/Jan/24 $$supposed:AB\mathrm{\perp }AC,AD\mathrm{\perp }BC$$$$\frac{45}{x}=\frac{x+48}{45}$$$$\Rightarrow{x}^{\mathrm{2}} +\mathrm{48}{x}−\mathrm{45}^{\mathrm{2}} =\mathrm{0} \…