Menu Close

Category: Geometry

Question-64246

Question Number 64246 by mr W last updated on 16/Jul/19 Answered by mr W last updated on 16/Jul/19 $${x}=\frac{\mathrm{1}}{\mathrm{sin}\:\theta} \\ $$$$\mathrm{tan}\:\frac{\theta}{\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{sin}\:\theta=\frac{\mathrm{2}×\frac{\mathrm{1}}{\mathrm{2}}}{\mathrm{1}+\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} }=\frac{\mathrm{4}}{\mathrm{5}} \\…

Question-64097

Question Number 64097 by ajfour last updated on 13/Jul/19 Commented by ajfour last updated on 13/Jul/19 $${Find}\:{side}\:{length}\:\boldsymbol{{s}}\:{of}\:{equal}\:{sided} \\ $$$${hexagon}\:{inscribed}\:{in}\:{ellipse}\:{of} \\ $$$${parameters}\:\boldsymbol{{a}}\:{and}\:\boldsymbol{{b}}. \\ $$ Answered by…

which-of-the-following-conditions-is-true-if-the-folowing-circle-are-verticale-x-2-y-2-a-1-x-b-1-y-c-1-0-x-2-y-2-a-2-x-b-2-y-c-2-o-1-a-1-a-2-b-1-b-2-2-c-1-c-2-2-a-1-a-2-b-1-b-2-3-

Question Number 129547 by Adel last updated on 16/Jan/21 $$\mathrm{which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{conditions}\:\mathrm{is}\:\mathrm{true}\: \\ $$$$\mathrm{if}\:\mathrm{the}\:\mathrm{folowing}\:\mathrm{circle}\:\mathrm{are}\:\mathrm{verticale} \\ $$$$ \\ $$$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{a}_{\mathrm{1}} \mathrm{x}+\mathrm{b}_{\mathrm{1}} \mathrm{y}+\mathrm{c}_{\mathrm{1}} =\mathrm{0} \\ $$$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{a}_{\mathrm{2}}…

Question-63981

Question Number 63981 by ajfour last updated on 11/Jul/19 Answered by mr W last updated on 11/Jul/19 $$\left[\sqrt{{a}^{\mathrm{2}} −{b}^{\mathrm{2}} −{b}^{\mathrm{2}} }+\sqrt{\left({a}−{r}\right)^{\mathrm{2}} −{r}^{\mathrm{2}} }\right]^{\mathrm{2}} =\left({b}+{r}\right)^{\mathrm{2}} −\left({b}−{r}\right)^{\mathrm{2}}…