Question Number 128193 by Algoritm last updated on 05/Jan/21 Answered by mr W last updated on 05/Jan/21 Commented by Algoritm last updated on 05/Jan/21 $$?=\:\:…
Question Number 128145 by mnjuly1970 last updated on 04/Jan/21 Commented by mnjuly1970 last updated on 04/Jan/21 $${number}\:{of}\:{triangles}…\uparrow\uparrow \\ $$ Commented by mr W last updated…
Question Number 62542 by mr W last updated on 22/Jun/19 Commented by mr W last updated on 22/Jun/19 $${the}\:{distances}\:{of}\:{a}\:{point}\:{M}\:{to}\:{the} \\ $$$${vertexes}\:{of}\:{a}\:{triangle}\:{are}\:{p},{q},{r}. \\ $$$${find}\:{the}\:{side}\:{lengthes}\:{and}\:{hence}\:{the} \\ $$$${perimeter}\:{of}\:{the}\:{triangle}\:{with}\:{the}…
Question Number 62523 by Tawa1 last updated on 22/Jun/19 Answered by $@ty@m last updated on 22/Jun/19 $${x}=\mathrm{90}−\left(\mathrm{90}−\mathrm{34}\right)=\mathrm{34} \\ $$$${y}={x}+\mathrm{90}=\mathrm{34}+\mathrm{90}=\mathrm{124} \\ $$ Terms of Service Privacy…
Question Number 62486 by ajfour last updated on 21/Jun/19 Commented by ajfour last updated on 21/Jun/19 $${Find}\:{maximum}\:{perimeter}\:{of} \\ $$$${quadrilateral}\:{ABCD}. \\ $$ Answered by mr W…
Question Number 62456 by ajfour last updated on 21/Jun/19 Commented by ajfour last updated on 21/Jun/19 $${If}\:{the}\:{regular}\:{tetrahedron}\:{with} \\ $$$${edge}\:{length}\:{unity}\:{inscribes}\:{a} \\ $$$${hemisphere}\:{such}\:{that}\:{three}\:{faces} \\ $$$${are}\:{tangent}\:{to}\:{the}\:{spherical} \\ $$$${surface}\:{while}\:{fourth}\:{serves}\:{to}…
Question Number 62448 by mr W last updated on 21/Jun/19 Commented by mr W last updated on 21/Jun/19 $${The}\:{distances}\:{of}\:{a}\:{point}\:{M}\:{to}\:{the} \\ $$$${vertexes}\:{of}\:{a}\:{triangle}\:{are}\:{p},{q},{r}. \\ $$$$\left({assume}\:{p}\geqslant{q}\geqslant{r}\right) \\ $$$${Find}\:{the}\:{side}\:{lengthes}\:{and}\:{thus}\:{the}…
Question Number 62380 by ajfour last updated on 20/Jun/19 $${Prove}\:{that}\:{if}\:{the}\:{lengths}\:{of}\:{a}\: \\ $$$${triangle}\:{form}\:{an}\:{arithmetic} \\ $$$${progression},\:{then}\:{the}\:{centre}\:{of} \\ $$$${incircle}\:{and}\:{the}\:{centroid}\:{of} \\ $$$${triangle}\:{lie}\:{on}\:{a}\:{line}\:{parallel}\:{to} \\ $$$${the}\:{side}\:{of}\:{middle}\:{length}\:{of}\:{the} \\ $$$${triangle}. \\ $$ Answered…
Question Number 62363 by Tawa1 last updated on 20/Jun/19 Answered by MJS last updated on 20/Jun/19 $$\mathrm{big}\:\mathrm{circle}\:\left(\mathrm{let}\:{R}=\mathrm{1}\right) \\ $$$${x}=\pm\sqrt{\mathrm{1}−{y}^{\mathrm{2}} } \\ $$$$\mathrm{lines}\:\mathrm{of}\:\mathrm{tbe}\:\mathrm{triangle} \\ $$$${x}=\pm\frac{\sqrt{\mathrm{3}}}{\mathrm{3}}{y} \\…
Question Number 127879 by Algoritm last updated on 02/Jan/21 Terms of Service Privacy Policy Contact: info@tinkutara.com