Question Number 64425 by Tawa1 last updated on 17/Jul/19 Commented by Prithwish sen last updated on 17/Jul/19 $$\mathrm{Area}\:\mathrm{of}\:\mathrm{shaded}\:\mathrm{portion}\:=\: \\ $$$$\mathrm{Area}\:\mathrm{of}\:\mathrm{square}\:−\:\mathrm{Area}\:\mathrm{of}\:\mathrm{quarter}\:\mathrm{circle} \\ $$$$=\:\mathrm{a}^{\mathrm{2}} \:−\:\frac{\pi\mathrm{a}^{\mathrm{2}} }{\mathrm{4}}\:\left[\:\mathrm{if}\:\boldsymbol{\mathrm{a}}\:\mathrm{be}\:\mathrm{the}\:\mathrm{side}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\right. \\…
Question Number 129910 by Algoritm last updated on 20/Jan/21 Commented by mr W last updated on 20/Jan/21 $${no}\:{unique}\:{solution}!\: \\ $$$${please}\:{make}\:{your}\:{graph}\:{clear}! \\ $$ Answered by mr…
Question Number 64289 by ajfour last updated on 16/Jul/19 Commented by ajfour last updated on 16/Jul/19 $${Find}\:{s}\:{in}\:{terms}\:{of}\:{radii}\:{a}\:{and}\:{b}. \\ $$ Commented by behi83417@gmail.com last updated on…
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Question Number 64246 by mr W last updated on 16/Jul/19 Answered by mr W last updated on 16/Jul/19 $${x}=\frac{\mathrm{1}}{\mathrm{sin}\:\theta} \\ $$$$\mathrm{tan}\:\frac{\theta}{\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{sin}\:\theta=\frac{\mathrm{2}×\frac{\mathrm{1}}{\mathrm{2}}}{\mathrm{1}+\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} }=\frac{\mathrm{4}}{\mathrm{5}} \\…
Question Number 64119 by ajfour last updated on 13/Jul/19 Commented by ajfour last updated on 13/Jul/19 $${In}\:{terms}\:{of}\:{the}\:{sides}\:{of}\:\bigtriangleup{ABC},\:{find} \\ $$$${the}\:{radius}\:{of}\:{the}\:{central}\:{circle}. \\ $$ Answered by ajfour last…
Question Number 64097 by ajfour last updated on 13/Jul/19 Commented by ajfour last updated on 13/Jul/19 $${Find}\:{side}\:{length}\:\boldsymbol{{s}}\:{of}\:{equal}\:{sided} \\ $$$${hexagon}\:{inscribed}\:{in}\:{ellipse}\:{of} \\ $$$${parameters}\:\boldsymbol{{a}}\:{and}\:\boldsymbol{{b}}. \\ $$ Answered by…
Question Number 64009 by ajfour last updated on 12/Jul/19 Commented by ajfour last updated on 12/Jul/19 $${Find}\:{R}\:{in}\:{terms}\:{of}\:{a}\:{and}\:{b}. \\ $$ Answered by mr W last updated…
Question Number 129547 by Adel last updated on 16/Jan/21 $$\mathrm{which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{conditions}\:\mathrm{is}\:\mathrm{true}\: \\ $$$$\mathrm{if}\:\mathrm{the}\:\mathrm{folowing}\:\mathrm{circle}\:\mathrm{are}\:\mathrm{verticale} \\ $$$$ \\ $$$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{a}_{\mathrm{1}} \mathrm{x}+\mathrm{b}_{\mathrm{1}} \mathrm{y}+\mathrm{c}_{\mathrm{1}} =\mathrm{0} \\ $$$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{a}_{\mathrm{2}}…
Question Number 63985 by Tawa1 last updated on 11/Jul/19 Answered by mr W last updated on 12/Jul/19 Commented by mr W last updated on 12/Jul/19…