Question Number 212822 by ajfour last updated on 24/Oct/24 Commented by ajfour last updated on 24/Oct/24 $${Consider}\:{triangle}\:{isosceles}\:{about} \\ $$$${upper}\:{vertex}. \\ $$ Commented by Ghisom last…
Question Number 212821 by Spillover last updated on 24/Oct/24 Answered by Spillover last updated on 25/Oct/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 212802 by Spillover last updated on 24/Oct/24 Answered by mr W last updated on 24/Oct/24 Commented by mr W last updated on 24/Oct/24…
Question Number 212801 by Spillover last updated on 24/Oct/24 Answered by som(math1967) last updated on 24/Oct/24 Commented by som(math1967) last updated on 24/Oct/24 $$\frac{{OL}}{{PL}}=\mathrm{tan}\:\mathrm{22}\frac{\mathrm{1}}{\mathrm{2}} \\…
Question Number 212803 by Spillover last updated on 24/Oct/24 Answered by Spillover last updated on 24/Oct/24 Answered by Spillover last updated on 24/Oct/24 Answered by…
Question Number 212760 by Spillover last updated on 23/Oct/24 Answered by mr W last updated on 23/Oct/24 Commented by mr W last updated on 23/Oct/24…
Question Number 212761 by Spillover last updated on 23/Oct/24 Commented by mr W last updated on 23/Oct/24 $${AB}=\mathrm{2}×{GE}=\mathrm{8}\sqrt{\mathrm{7}} \\ $$ Answered by som(math1967) last updated…
Question Number 212784 by Spillover last updated on 23/Oct/24 Answered by A5T last updated on 24/Oct/24 $${d}^{\mathrm{2}} =\left({r}−{a}\right)^{\mathrm{2}} +{r}^{\mathrm{2}} −\mathrm{2}{r}\left({r}−{a}\right){cos}\theta \\ $$$${c}^{\mathrm{2}} =\left({r}−{a}\right)^{\mathrm{2}} +{r}^{\mathrm{2}} +\mathrm{2}{r}\left({r}−{a}\right){cos}\theta…
Question Number 212783 by Spillover last updated on 23/Oct/24 Commented by York12 last updated on 25/Oct/24 $$ \\ $$$$ \\ $$$$ \\ $$ Answered by…
Question Number 212733 by cherokeesay last updated on 22/Oct/24 Answered by A5T last updated on 22/Oct/24 Commented by A5T last updated on 22/Oct/24 $$\left({R}−\sqrt{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{2}\left(\sqrt{\mathrm{2}}\right)^{\mathrm{2}}…