Category: Geometry

Question Number 216105 by mr W last updated on 27/Jan/25 Answered by A5T last updated on 27/Jan/25 $${\mathrm{x}}^2=2{\left(\frac{\mathrm{x}+1}{2}\right)}^2\Rightarrow {\mathrm{x}}^2=\frac{{\mathrm{x}}^2+2\mathrm{x}+1}{2}\Rightarrow {\mathrm{x}}^2-2\mathrm{x}-1=0$$$$\Rightarrow\mathrm{x}=\frac{\mathrm{2}\underset{−}…

Question Number 215769 by momoga last updated on 17/Jan/25 In △ABC, it is given that AC⊥CB, CD⊥AB, and CD = 12, AC = BC +…

Question Number 215641 by cherokeesay last updated on 12/Jan/25 Answered by mr W last updated on 12/Jan/25 $$AC=\sqrt{1^2+{(1+1)}^2}=\sqrt{5}$$$$DC\times AC=1\times (1+1+1)$$$$\Rightarrow{DC}=\frac{\mathrm{3}}{\:\sqrt{\mathrm{5}}}=\frac{\mathrm{3}\sqrt{\mathrm{5}}}{\mathrm{5}} \…

Question Number 215445 by BaliramKumar last updated on 07/Jan/25 Answered by A5T last updated on 07/Jan/25 $$\sqrt{{(\mathrm{x}+\mathrm{r})}^2-{\mathrm{r}}^2}=\sqrt{{(\mathrm{r}+\mathrm{r})}^2-{\mathrm{r}}^2}-(\mathrm{r}+\mathrm{x})$$$$\Rightarrow \sqrt{\mathrm{x}(\mathrm{x}+2\mathrm{r})}=\mathrm{r}\sqrt{3}-\mathrm{r}-\mathrm{x}$$$$\Rightarrow\mathrm{4r}−\mathrm{2r}\sqrt{\mathrm{3}}−\mathrm{2x}\sqrt{\mathrm{3}}=\mathrm{0}…

Question Number 215400 by ajfour last updated on 05/Jan/25 Commented by ajfour last updated on 05/Jan/25 $$CorrectionIthink-Findb,givena.$$ Answered by mr W last updated…