Question Number 209637 by mr W last updated on 17/Jul/24 Commented by mr W last updated on 17/Jul/24 $${find}\:{minimum}\:{of}\:{AB}+{BC}+{CD}=? \\ $$ Commented by Frix last…
Question Number 209582 by behi834171 last updated on 15/Jul/24 Commented by mr W last updated on 15/Jul/24 $${question}\:{is}\:{strange}.\:{there}\:{is}\:{no} \\ $$$${unique}\:{value}\:{for}\:{x}. \\ $$$$\mathrm{0}<{x}<\mathrm{5}\sqrt{\mathrm{3}} \\ $$ Commented…
Question Number 209495 by Tawa11 last updated on 11/Jul/24 Commented by Tawa11 last updated on 11/Jul/24 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{missing}\:\mathrm{angle}\:\left(\mathrm{the}\:\mathrm{red}\right) \\ $$ Answered by mr W last updated…
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Question Number 209336 by Tawa11 last updated on 07/Jul/24 Commented by Tawa11 last updated on 07/Jul/24 $$\mathrm{Find}\:\mathrm{area}\:\mathrm{of}\:\mathrm{shadded}. \\ $$ Answered by mr W last updated…
Question Number 209329 by Huy250 last updated on 07/Jul/24 $${Given}\:{an}\:{acute}\:{triangle}\:{with}\:{AB}\:<{AC} \\ $$$${is}\:{inscribed}\:{in}\:{the}\:{circle}\:\left({O}\right).\:{Let}\:{D} \\ $$$${and}\:{E}\:{be}\:{the}\:{midpoints}\:{of}\:{the}\:{minor}\:{arc} \\ $$$${and}\:{major}\:{arc}\:{BC},\:{respectively}.\:{Let}\:{I}\:{and}\:{J} \\ $$$${be}\:{the}\:{incenters}\:{of}\:{trianges}\:{ABD}\:{and}\:{ACD}, \\ $$$${respectively}.\:{Prove}\:{that}\:{EI}={EJ}. \\ $$ Commented by Huy250…
Question Number 209288 by Jubr last updated on 06/Jul/24 Answered by A5T last updated on 06/Jul/24 $$\frac{{x}}{{r}}=\frac{\mathrm{8}}{{r}}\Rightarrow{x}=\mathrm{8} \\ $$$${r}^{\mathrm{2}} =\left(\mathrm{2}{x}\right)^{\mathrm{2}} +\left({r}−\mathrm{8}\right)^{\mathrm{2}} \Rightarrow{r}=\mathrm{20} \\ $$$$\left[{Yellow}\right]=\frac{\mathrm{90}}{\mathrm{360}}×\mathrm{400}\pi−\frac{\mathrm{20}×\mathrm{20}}{\mathrm{2}}=\mathrm{100}\pi−\mathrm{200} \\…
Question Number 209289 by Jubr last updated on 06/Jul/24 Answered by A5T last updated on 06/Jul/24 $$\frac{{s}}{{x}}=\frac{\mathrm{7}}{\mathrm{21}}\Rightarrow{x}=\mathrm{3}{s} \\ $$$$\frac{{s}}{{y}}=\frac{\mathrm{14}}{\mathrm{21}}\Rightarrow{y}=\frac{\mathrm{3}{s}}{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{21}^{\mathrm{2}} \Rightarrow\mathrm{9}{s}^{\mathrm{2}} +\frac{\mathrm{9}{s}^{\mathrm{2}}…
Question Number 209314 by SonGoku last updated on 06/Jul/24 Commented by SonGoku last updated on 06/Jul/24 $$\mathrm{How}\:\mathrm{to}\:\mathrm{find}\:\mathrm{the}\:\mathrm{of}\:\mathrm{this}\:\mathrm{polygon}? \\ $$ Commented by mr W last updated…
Question Number 209272 by Tawa11 last updated on 05/Jul/24 Commented by Tawa11 last updated on 05/Jul/24 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{shaded}\:\mathrm{area}. \\ $$ Answered by A5T last updated on…