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Category: Geometry

Question-196275

Question Number 196275 by AROUNAMoussa last updated on 21/Aug/23 Answered by MM42 last updated on 21/Aug/23 ABD=35AD=ABBCD=55ABAC=sinxsin130&ADAC=sin(55x)sin65sinx×sin65=2sin65×cos65×sin(55x)$$\Rightarrow{sinx}=\mathrm{2}{cos}\mathrm{65}{sin}\left(\mathrm{55}−{x}\right)={sin}\left(\mathrm{55}−{x}+\mathrm{65}\right)+{sin}\left(\mathrm{55}−{x}−\mathrm{65}\right)…