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Category: Geometry

Question-65334

Question Number 65334 by Tawa1 last updated on 28/Jul/19 Answered by mr W last updated on 28/Jul/19 D=36012642×2=150°DCsinx=ACsin150DC=sinxsin150×AC$$\frac{{AC}}{\mathrm{sin}\:\mathrm{126}}=\frac{{AB}}{\mathrm{sin}\:\left[\mathrm{42}−\left(\mathrm{30}−{x}\right)\right]}=\frac{{AB}}{\mathrm{sin}\:\left({x}+\mathrm{12}\right)} \