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Category: Geometry

Question-192828

Question Number 192828 by Ari last updated on 28/May/23 Commented by Ari last updated on 28/May/23 Can we find the side x in the problem given in the figure? Answered by MM42 last updated on 28/May/23 $${cosE}=\frac{\mathrm{25}+\mathrm{64}−\mathrm{49}}{\mathrm{2}×\mathrm{5}×\mathrm{8}}=\frac{\mathrm{40}}{\mathrm{80}}=\frac{\mathrm{1}}{\mathrm{2}}…

Question-192819

Question Number 192819 by cherokeesay last updated on 28/May/23 Answered by a.lgnaoui last updated on 28/May/23 $$\bigtriangleup\mathrm{PBM}\:\:\mathrm{recrangle}\:\mathrm{en}\:\mathrm{B} \\ $$$$\measuredangle\mathrm{PMB}=\lambda \\ $$$$\bigtriangleup\mathrm{MAD}\:\:\mathrm{MA}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{AD}\Rightarrow\measuredangle\mathrm{AMD}=\measuredangle\mathrm{MDC}=\frac{\pi}{\mathrm{3}} \\ $$$$\mathrm{MD}=\sqrt{\mathrm{AD}^{\mathrm{2}} +\left(\frac{\mathrm{AD}}{\mathrm{2}}\right)^{\mathrm{2}} }=\frac{\mathrm{AD}\sqrt{\mathrm{5}}}{\mathrm{2}}\:\:\left(\mathrm{AD}=\mathrm{AB}\right)…

Question-61612

Question Number 61612 by Tawa1 last updated on 05/Jun/19 Commented by MJS last updated on 05/Jun/19 $$\mathrm{a}\:\mathrm{hanging}\:\mathrm{rope}\:\mathrm{forms} \\ $$$${y}={a}\mathrm{cosh}\:\frac{{x}}{{a}} \\ $$$$\mathrm{if}\:\mathrm{we}\:\mathrm{put}\:\mathrm{the}\:\mathrm{towers}\:\:\mathrm{at}\:{x}=\pm\frac{{d}}{\mathrm{2}} \\ $$ Commented by…