Question Number 125384 by ajfour last updated on 10/Dec/20 Commented by ajfour last updated on 10/Dec/20 $${The}\:{hemisphere}\:{has}\:{radius}\:\mathrm{2}. \\ $$$${The}\:{outer}\:{circular}\:{base}\:{has}\:{radius} \\ $$$$\mathrm{3}.\:{Find}\:{maximum}\:{side}\:{length}\:{of} \\ $$$${equilateral}\:{triangle}\:{with}\:{vertices} \\ $$$${placed}\:{as}\:{shown}.…
Question Number 190890 by Rupesh123 last updated on 13/Apr/23 Commented by Frix last updated on 13/Apr/23 $${n}=\mathrm{6}\wedge{m}=−\mathrm{6} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 190856 by TUN last updated on 13/Apr/23 $${Give}\:{M}\:{is}\:{any}\:{point}\:{in}\:{ABC}\:{triangle} \\ $$$${Prove}\:{that}:\:{MA}+{MB}+{MC}<{AC}+{BC} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 59700 by ajfour last updated on 13/May/19 Commented by ajfour last updated on 13/May/19 $$\mathrm{Find}\:\mathrm{maximum}\:\mathrm{overlap}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{quarter}\:\mathrm{circle}\:\mathrm{and}\:\mathrm{semicircle}\:\mathrm{both} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{same}\:\mathrm{radius}\:\mathrm{and}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{shown}\:\mathrm{orientation}\:\mathrm{as}\:\mathrm{a}\:\mathrm{percentage} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{quarter}\:\mathrm{circle}\:\mathrm{area}.…
Question Number 190745 by TUN last updated on 10/Apr/23 $${Give}\:{M}\:{is}\:{any}\:{point}\:{in}\:{ABC}\:{triangle}.\:{Prove}\:{that}\:{MA}+{MB}+{MC}<{AC}+{BC} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 59620 by ajfour last updated on 12/May/19 Commented by ajfour last updated on 12/May/19 $$\mathrm{Find}\:\mathrm{dimensions}\:\mathrm{of}\:\mathrm{largest}\:\mathrm{volume} \\ $$$$\mathrm{cylinder}\:\mathrm{inscribed}\:\mathrm{within}\:\mathrm{a}\:\mathrm{hemi}- \\ $$$$\mathrm{sphere}\:\mathrm{of}\:\mathrm{radius}\:\mathrm{R}\:\left(\mathrm{in}\:\mathrm{shown}\:\mathrm{orientation}\right). \\ $$ Commented by…
Question Number 190644 by cherokeesay last updated on 08/Apr/23 Answered by a.lgnaoui last updated on 09/Apr/23 $$\mathrm{Algebrique}\:\mathrm{solution} \\ $$$$\mathrm{CercleC}_{\mathrm{1}} \:\:\mathrm{B}:\mathrm{origine}\:\mathrm{du}\:\mathrm{Ref}\:\mathrm{B}\left(\mathrm{0},\mathrm{0}\right) \\ $$$$\mathrm{et}\:\mathrm{de}\:\mathrm{rayon}\:\mathrm{1}\:\:\:\mathrm{C}_{\mathrm{1}} \left(\mathrm{B},\mathrm{1}\right)\:\left(\:\mathrm{B},\mathrm{E}\right):\mathrm{C}_{\mathrm{1}} \cap\mathrm{C}_{\mathrm{2}} \\…
Question Number 125090 by Mammadli last updated on 08/Dec/20 Commented by mr W last updated on 08/Dec/20 $${not}\:{true},\:{so}\:{we}\:{can}'{t}\:{prove}. \\ $$ Commented by Mammadli last updated…
Question Number 190615 by mr W last updated on 07/Apr/23 Commented by mr W last updated on 08/Apr/23 $$\mathrm{1}.\:{find}\:{ratio}\:\frac{{a}_{\mathrm{1}} }{{a}}=?\:{such}\:{that}\:{the}\:{right} \\ $$$${circular}\:{cone}\:{is}\:{cut}\:{into}\:{two}\:{parts}\: \\ $$$${with}\:{equal}\:{volume}\:{as}\:{shown}. \\…
Question Number 125070 by Algoritm last updated on 08/Dec/20 Commented by mr W last updated on 08/Dec/20 $${x}\bot{y}\bot{z}\:{is}\:{not}\:{possible}. \\ $$$${do}\:{you}\:{mean}\:{x}\bot{a},\:{y}\bot{b},\:{z}\bot{c}? \\ $$$${but}\:{any}\:{way},\:{you}\:{can}\:{not}\:{determine} \\ $$$${the}\:{area}\:{of}\:{triangle}\:{with}\:{given} \\…