Category: Geometry

Question Number 64425 by Tawa1 last updated on 17/Jul/19 Commented by Prithwish sen last updated on 17/Jul/19 $$\mathrm{Area}\mathrm{of}\mathrm{shaded}\mathrm{portion}=$$$$\mathrm{Area}\mathrm{of}\mathrm{square}-\mathrm{Area}\mathrm{of}\mathrm{quarter}\mathrm{circle}$$$$=\:\mathrm{a}^{\mathrm{2}} \:−\:\frac{\pi\mathrm{a}^{\mathrm{2}} }{\mathrm{4}}\:\left[\:\mathrm{if}\:\boldsymbol{\mathrm{a}}\:\mathrm{be}\:\mathrm{the}\:\mathrm{side}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\right. \…

Question Number 64289 by ajfour last updated on 16/Jul/19 Commented by ajfour last updated on 16/Jul/19 $$Findsintermsofradiiaandb.$$ Commented by behi83417@gmail.com last updated on…

Question Number 64246 by mr W last updated on 16/Jul/19 Answered by mr W last updated on 16/Jul/19 $$x=\frac{1}{\sin \theta }$$$$\tan \frac{\theta }{2}=\frac{1}{2}$$$$\Rightarrow\mathrm{sin}\:\theta=\frac{\mathrm{2}×\frac{\mathrm{1}}{\mathrm{2}}}{\mathrm{1}+\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} }=\frac{\mathrm{4}}{\mathrm{5}} \…

Question Number 64097 by ajfour last updated on 13/Jul/19 Commented by ajfour last updated on 13/Jul/19 $$Findsidelength\mathit{s}ofequalsided$$$$hexagoninscribedinellipseof$$$$parameters\mathit{a}and\mathit{b}.$$ Answered by…

Question Number 129547 by Adel last updated on 16/Jan/21 $$\mathrm{which}\mathrm{of}\mathrm{the}\mathrm{following}\mathrm{conditions}\mathrm{is}\mathrm{true}$$$$\mathrm{if}\mathrm{the}\mathrm{folowing}\mathrm{circle}\mathrm{are}\mathrm{verticale}$$$$$$$${\mathrm{x}}^2+{\mathrm{y}}^2+{\mathrm{a}}_1\mathrm{x}+{\mathrm{b}}_1\mathrm{y}+{\mathrm{c}}_1=0$$$$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{a}_{\mathrm{2}}…