Menu Close

Category: Geometry

Question-63194

Question Number 63194 by lalitchand last updated on 30/Jun/19 Answered by mr W last updated on 30/Jun/19 ΔAQRΔABC=(AQAB)2=(23)2=49$$\frac{\Delta{APS}}{\Delta{ABC}}=\left(\frac{{AP}}{{AB}}\right)^{\mathrm{2}} =\left(\frac{\mathrm{1}}{\mathrm{3}}\right)^{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{9}} \