Question Number 189791 by normans last updated on 21/Mar/23 Answered by a.lgnaoui last updated on 22/Mar/23 $$\mathrm{20}\:{colors}\:{to}\:{distingue}\: \\ $$$$\mathrm{3}×\mathrm{3}+\mathrm{2}+\mathrm{2}×\mathrm{2}+\mathrm{5} \\ $$ Terms of Service Privacy…
Question Number 189790 by normans last updated on 21/Mar/23 Answered by mr W last updated on 22/Mar/23 Commented by mr W last updated on 22/Mar/23…
Question Number 189777 by mnjuly1970 last updated on 21/Mar/23 $$ \\ $$$$\:\:\:\mathrm{Question}\:\:\left(\mathrm{Graph}\:\right)… \\ $$$$ \\ $$$$\:\:\:\:\mathrm{How}\:\mathrm{many}\:\mathrm{four}\:\mathrm{member}\:\mathrm{dominating}\:\mathrm{sets} \\ $$$$\:\:\:\: \\ $$$$\:\:\:\:\:\:\mathrm{are}\:\:\mathrm{there}\:\:\mathrm{in}\:\mathrm{the}\:\:\mathrm{graph}\:\mathrm{of}\:\:\mathrm{C}_{\:\mathrm{7}} \:? \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:−−−−−−…
Question Number 58696 by ajfour last updated on 27/Apr/19 Commented by ajfour last updated on 27/Apr/19 $$\angle\mathrm{AOB}=\mathrm{90}°\:\mathrm{and}\:\mathrm{ABCD}\:\mathrm{is}\:\mathrm{a}\:\mathrm{square}. \\ $$$$\mathrm{If}\:\mathrm{DGF}\:\bot\:\mathrm{OB},\:\mathrm{find}\:\theta. \\ $$ Commented by ajfour last…
Question Number 189761 by normans last updated on 21/Mar/23 $$ \\ $$$$\:\:\frac{\boldsymbol{{x}}}{\mathrm{1}×\mathrm{2}}\:+\:\frac{\boldsymbol{{x}}}{\mathrm{2}×\mathrm{3}}\:+\:\frac{\boldsymbol{{x}}}{\mathrm{3}×\mathrm{4}}\:+\:……+\:\frac{\boldsymbol{{x}}}{\mathrm{1998}×\mathrm{1999}}\:+\:\frac{\boldsymbol{{x}}}{\mathrm{1999}×\mathrm{2000}}\:=\:\mathrm{1}\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{x}}\:=\:???? \\ $$$$ \\ $$ Answered by Frix last updated on 21/Mar/23…
Question Number 58686 by Tawa1 last updated on 27/Apr/19 Commented by Tawa1 last updated on 27/Apr/19 $$\mathrm{Diagram}\:\mathrm{for}\:\mathrm{number}\:\mathrm{1}\:\mathrm{is}\:\mathrm{below} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 189743 by normans last updated on 21/Mar/23 Answered by mr W last updated on 21/Mar/23 Commented by mr W last updated on 21/Mar/23…
Question Number 189720 by Rupesh123 last updated on 21/Mar/23 Answered by HeferH last updated on 21/Mar/23 $$\mathrm{Area}\left(\mathrm{EBC}\right)\:=\:\frac{\mathrm{4}×\mathrm{12}}{\mathrm{2}}\:=\:\mathrm{24u}^{\mathrm{2}} \\ $$ Commented by HeferH last updated on…
Question Number 189715 by Rupesh123 last updated on 20/Mar/23 Answered by som(math1967) last updated on 21/Mar/23 $$\bigtriangleup{ABC}\cong\bigtriangleup{DBE} \\ $$$$\Rightarrow{AB}={DB} \\ $$$${BC}={BE}\:\Rightarrow\angle{BEC}=\angle{BCE} \\ $$$$\angle{ACB}=\mathrm{34}\:\left[\angle{ACB}=\angle{CBE}\right]\:\: \\ $$$$\angle{DEB}=\angle{ACB}=\mathrm{34}…