Question Number 189704 by normans last updated on 20/Mar/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 189693 by mr W last updated on 20/Mar/23 Commented by mr W last updated on 20/Mar/23 $${additional}\:{question}\:{to}\:{Q}\mathrm{189608}: \\ $$$${what}\:{is}\:{the}\:{shortest}\:{way}\:{length}\:{for}\: \\ $$$${the}\:{ant}\:{from}\:{A}\:{to}\:{B}? \\ $$…
Question Number 189685 by normans last updated on 20/Mar/23 Answered by manxsol last updated on 21/Mar/23 Answered by a.lgnaoui last updated on 20/Mar/23 Commented by…
Question Number 189684 by normans last updated on 20/Mar/23 Commented by a.lgnaoui last updated on 21/Mar/23 Answered by mr W last updated on 20/Mar/23 Commented…
Question Number 189680 by normans last updated on 20/Mar/23 Commented by normans last updated on 20/Mar/23 $${sorry}\:{to}\:{Q}\mathrm{189551}. \\ $$$$\:{this}\:{is}\:{true}\:{problem}….. \\ $$ Commented by mr W…
Question Number 189667 by Rupesh123 last updated on 20/Mar/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 189666 by Rupesh123 last updated on 20/Mar/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 58567 by olalekan2 last updated on 25/Apr/19 $$\:{A}\:{regular}\:{polygon}\:{of}\:\left(\mathrm{2}{k}+\mathrm{1}\right)\:{sides} \\ $$$${has}\:\mathrm{140}\:{as}\:{the}\:{size}\:{of}\:{each}\:{interior} \\ $$$${angle}.{Find}\:{k} \\ $$ Commented by mr W last updated on 25/Apr/19 $$\left(\mathrm{2}{k}+\mathrm{1}\right)\left(\mathrm{180}−\mathrm{140}\right)=\mathrm{360}…
Question Number 189615 by Rupesh123 last updated on 19/Mar/23 Answered by HeferH last updated on 19/Mar/23 $$\mathrm{16}−\mathrm{x}\sqrt{\mathrm{5}}\:=\:\frac{\mathrm{8x}}{\mathrm{3}\sqrt{\mathrm{5}}}−\frac{\mathrm{x}}{\:\sqrt{\mathrm{5}}} \\ $$$$\mathrm{16}−\mathrm{x}\sqrt{\mathrm{5}}\:=\:\frac{\mathrm{5x}}{\mathrm{3}\sqrt{\mathrm{5}}} \\ $$$$\:\mathrm{48}\sqrt{\mathrm{5}}\:−\:\mathrm{15x}\:=\:\mathrm{5x} \\ $$$$\:\mathrm{x}\:=\:\frac{\mathrm{48}\sqrt{\mathrm{5}}}{\mathrm{20}} \\ $$$$\mathrm{x}\sqrt{\mathrm{5}}\:=\:\frac{\mathrm{48}\centerdot\mathrm{5}}{\mathrm{20}}\:=\frac{\mathrm{48}}{\mathrm{4}}\:=\:\mathrm{12}\:…
Question Number 189608 by mr W last updated on 19/Mar/23 Commented by mr W last updated on 19/Mar/23 $${a}\:{bin}\:{has}\:{the}\:{shape}\:{of}\:{a}\:{frustum} \\ $$$${as}\:{shown}.\:{an}\:{ant}\:{climbs}\:{on}\:{the}\:{outer} \\ $$$${surface}\:{of}\:{the}\:{bin}\:{from}\:{point} \\ $$$${A}\:{to}\:{point}\:{B}\:{following}\:{a}\:{path}\:{with}…