Category: Geometry

Question Number 194056 by ajfour last updated on 26/Jun/23 Answered by a.lgnaoui last updated on 27/Jun/23 $$\mathrm{ABC}\mathrm{triangle}\mathrm{equilaterale}$$$$\mathrm{AB}=\mathrm{BC}=\mathrm{AC}\mathrm{BC}=2\mathrm{acos}30=\mathrm{a}\sqrt{3}$$$$\Rightarrow \mathrm{AH}=\mathrm{BCsin}60=\frac{3\mathrm{a}}{2}$$$$\mathrm{AI}=\mathrm{AM}+\mathrm{MI}=2\mathrm{a}\left(\mathrm{i}\right)$$$$\:\:\measuredangle\mathrm{MAN}=\mathrm{30}\:;\mathrm{sin}\:\mathrm{30}=\frac{\mathrm{c}}{\mathrm{AM}}\Rightarrow\:\mathrm{AM}=\mathrm{2}\boldsymbol{\mathrm{c}}…

Question Number 193975 by mr W last updated on 24/Jun/23 Commented by mr W last updated on 25/Jun/23 $$findtheareaofthehatchedsquare.$$ Answered by mr W…

Question Number 193906 by cherokeesay last updated on 22/Jun/23 Answered by Subhi last updated on 22/Jun/23 $$$$$$\frac{1}{sin\left(18\right)}=\frac{1+y}{sin(144-x)}$$$$\frac{1}{sin\left(18\right)}=\frac{y}{sin\left(x\right)}\Rrightarrow y=\frac{sin\left(x\right)}{sin\left(18\right)}$$$$\frac{1}{sin\left(18\right)}=\frac{1+\frac{sin\left(x\right)}{sin\left(18\right)}}{sin(144-x)}$$$${sin}\left(\mathrm{144}−{x}\right)={sin}\left(\mathrm{18}\right)+{sin}\left({x}\right)…

Question Number 193726 by mr W last updated on 18/Jun/23 Answered by som(math1967) last updated on 18/Jun/23 $$a+b+c$$$$={\tan }^{-1}\frac{1}{3}+{\tan }^{-1}\frac{1}{2}+{\tan }^{-1}1$$$$=\mathrm{tan}^{−\mathrm{1}}…

Question Number 193706 by Rupesh123 last updated on 18/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com