Question Number 189558 by normans last updated on 18/Mar/23 Answered by a.lgnaoui last updated on 19/Mar/23 $$\bullet\left({BCEF}\right){est}\:{un}\:{trapeze} \\ $$$$\:\:{Aire}\left({BCEF}\right)=\left(\frac{{BC}+{EF}}{\mathrm{2}}\right)×{CE} \\ $$$$=\frac{\left(\mathrm{2},\mathrm{5}+{y}\right)\left({x}+\mathrm{2}\right)}{\mathrm{2}}={A}_{\mathrm{1}} +{A}_{\mathrm{2}} +\mathrm{9}\left(\mathrm{1}\right) \\ $$$$\:\:{A}_{\mathrm{1}}…
Question Number 189551 by normans last updated on 18/Mar/23 Commented by mr W last updated on 18/Mar/23 $${queston}\:{is}\:{wrong}!\:{no}\:{solution}! \\ $$$${with}\:{any}\:{two}\:{circles}\:{you}\:{can}\:{make} \\ $$$${this}\:{angle}\:\mathrm{150}°. \\ $$ Terms…
Question Number 189535 by normans last updated on 18/Mar/23 Answered by mr W last updated on 18/Mar/23 Commented by mr W last updated on 18/Mar/23…
Question Number 189517 by mr W last updated on 18/Mar/23 Commented by mr W last updated on 18/Mar/23 $${an}\:{unsolved}\:{old}\:{question} \\ $$ Answered by mr W…
Question Number 189509 by normans last updated on 18/Mar/23 Answered by mr W last updated on 18/Mar/23 Commented by mr W last updated on 18/Mar/23…
Question Number 189484 by mr W last updated on 17/Mar/23 Commented by mr W last updated on 17/Mar/23 $${an}\:{unsolved}\:{old}\:{question} \\ $$ Answered by mr W…
Question Number 189465 by normans last updated on 17/Mar/23 Answered by HeferH last updated on 17/Mar/23 Commented by HeferH last updated on 17/Mar/23 $$\:\mathrm{A}_{\mathrm{seg}} \:=\:\mathrm{A}_{\mathrm{sec}}…
Question Number 189438 by normans last updated on 16/Mar/23 Answered by som(math1967) last updated on 16/Mar/23 $${construct}\:{FM}\parallel{BE} \\ $$$$\bigtriangleup{AFM}\sim\bigtriangleup{ABE} \\ $$$$\frac{{AM}}{{AE}}=\frac{\mathrm{3}}{\mathrm{3}+\mathrm{5}}=\frac{\mathrm{3}}{\mathrm{8}} \\ $$$$\frac{{AM}}{{ME}}=\frac{\mathrm{3}}{\mathrm{5}} \\ $$$${EO}\parallel{FM}…
Question Number 189421 by normans last updated on 16/Mar/23 Commented by mr W last updated on 16/Mar/23 $${terrible}\:{diagram}:\: \\ $$$${not}\:{clear}\:{if}\:{circle}\:{tangents}\:{the}\:{semi} \\ $$$${circle}. \\ $$$${not}\:{clear}\:{which}\:{angle}\:{is}\:{meant}. \\…
Question Number 189409 by cherokeesay last updated on 15/Mar/23 Answered by HeferH last updated on 15/Mar/23 Commented by HeferH last updated on 15/Mar/23 $$\frac{\mathrm{y}}{\mathrm{4}}\:=\:\frac{\mathrm{6}}{\mathrm{21}} \\…