Question Number 58313 by mr W last updated on 21/Apr/19 Commented by tanmay last updated on 21/Apr/19 Commented by tanmay last updated on 21/Apr/19 $${wait}\:{sir}\:{trying}\:{to}\:{find}\:{x}……
Question Number 123843 by mnjuly1970 last updated on 28/Nov/20 Commented by mnjuly1970 last updated on 28/Nov/20 $${please}\:{solve}\Uparrow\Uparrow \\ $$ Answered by mr W last updated…
Question Number 58282 by behi83417@gmail.com last updated on 20/Apr/19 $$\boldsymbol{\mathrm{A}}\:\boldsymbol{\mathrm{circle}}\:\boldsymbol{\mathrm{tangents}}\:\boldsymbol{\mathrm{to}}\::\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{y}}\:\boldsymbol{\mathrm{axes}}\:\boldsymbol{\mathrm{and}} \\ $$$$\:\:\:\:\boldsymbol{\mathrm{x}}^{\frac{\mathrm{1}}{\mathrm{2}}} +\boldsymbol{\mathrm{y}}^{\frac{\mathrm{1}}{\mathrm{2}}} =\boldsymbol{\mathrm{a}}^{\frac{\mathrm{1}}{\mathrm{2}}} .\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{its}}\:\boldsymbol{\mathrm{radious}}. \\ $$ Answered by mr W last updated on 21/Apr/19…
Question Number 123809 by Dwaipayan Shikari last updated on 28/Nov/20 $$\frac{{log}\mathrm{2}}{\mathrm{1}^{\mathrm{2}} }−\frac{{log}\mathrm{3}}{\mathrm{2}^{\mathrm{2}} }+\frac{{log}\mathrm{4}}{\mathrm{3}^{\mathrm{2}} }−\frac{{log}\mathrm{5}}{\mathrm{4}^{\mathrm{2}} }+… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 123806 by Algoritm last updated on 28/Nov/20 Commented by Algoritm last updated on 28/Nov/20 $$\mathrm{ABCD}\:\mathrm{is}\:\mathrm{drawn}\:\mathrm{inside}\:\mathrm{a}\:\mathrm{rectangular}\:\mathrm{circle} \\ $$ Commented by mr W last updated…
Question Number 189319 by normans last updated on 14/Mar/23 Commented by mr W last updated on 15/Mar/23 $${ellipse}\:{is}\:{not}\:{uniquely}\:{defined},\:{hence} \\ $$$${no}\:{solution}! \\ $$ Commented by mr…
Question Number 189309 by cherokeesay last updated on 14/Mar/23 Answered by som(math1967) last updated on 14/Mar/23 Commented by som(math1967) last updated on 14/Mar/23 $${OA}={a}+\mathrm{2}{r}\: \\…
Question Number 189304 by ajfour last updated on 14/Mar/23 Commented by ajfour last updated on 14/Mar/23 $${Find}\:{largest}\:{radius}\:{ball}\:{beneath} \\ $$$${cone}\:{and}\:{wirhin}\:{cyclinder}. \\ $$ Answered by mr W…
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Question Number 189290 by normans last updated on 14/Mar/23 Answered by a.lgnaoui last updated on 14/Mar/23 $$\:\:\bigtriangleup\boldsymbol{{ABC}}\:\:\left[\measuredangle{OAC}={x}\:\:\:\measuredangle{BAO}={y}\right] \\ $$$$\:\:\:\:\:\:\:\:{x}+{y}=\mathrm{180}−\mathrm{126}=\mathrm{54}\:\: \\ $$$$\:\:\bigtriangleup\boldsymbol{{AOB}}\::\:\:\:\:\frac{\mathrm{sin}\:\mathrm{25}}{{OA}}=\frac{\mathrm{sin}\:{y}}{{OB}}\:\:\:\:\:\:\:\:\:\left(\mathrm{1}\right) \\ $$$$\:\:\bigtriangleup\boldsymbol{{AOC}}\::\:\:\:\frac{\mathrm{sin}\:\mathrm{17}}{{OA}}=\frac{\mathrm{sin}\:{x}}{{OC}}\:\:\:\:\:\:\:\:\:\:\left(\mathrm{2}\right) \\ $$$$\:\:\:\:\frac{\left(\mathrm{1}\right)}{\left(\mathrm{2}\right)}\Rightarrow\frac{\mathrm{sin}\:\mathrm{25}}{\mathrm{sin}\:\mathrm{17}}=\frac{\mathrm{sin}\:{y}}{\mathrm{sin}\:{x}}×\frac{{OC}}{{OB}}\:\:\:\:\:\:\:\:\left(\mathrm{3}\right)…