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Category: Geometry

Question-191962

Question Number 191962 by ajfour last updated on 04/May/23 Answered by mr W last updated on 04/May/23 $$\left[\sqrt{\left({a}+{x}\right)^{\mathrm{2}} −\left({a}−{x}\right)^{\mathrm{2}} }−\sqrt{\left({a}+{b}\right)^{\mathrm{2}} −\left({a}−{b}\right)^{\mathrm{2}} }\right]^{\mathrm{2}} =\left({b}+{x}\right)^{\mathrm{2}} −\left(\mathrm{2}{a}−{b}−{x}\right)^{\mathrm{2}} \

Question-191856

Question Number 191856 by TUN last updated on 02/May/23 Answered by Subhi last updated on 02/May/23 putAD=yBDsin(30)=ysin(10)BD=sin(30)sin(10)yby[sinlaw]$$\frac{{CD}}{{sin}\left(\mathrm{50}\right)}=\frac{{y}}{{sin}\left({x}\right)}\:.{hence}\:{CD}=\frac{{sin}\left(\mathrm{50}\right)}{{sin}\left({x}\right)}{y}…