Question Number 189509 by normans last updated on 18/Mar/23 Answered by mr W last updated on 18/Mar/23 Commented by mr W last updated on 18/Mar/23…
Question Number 189484 by mr W last updated on 17/Mar/23 Commented by mr W last updated on 17/Mar/23 $${an}\:{unsolved}\:{old}\:{question} \\ $$ Answered by mr W…
Question Number 189465 by normans last updated on 17/Mar/23 Answered by HeferH last updated on 17/Mar/23 Commented by HeferH last updated on 17/Mar/23 $$\:\mathrm{A}_{\mathrm{seg}} \:=\:\mathrm{A}_{\mathrm{sec}}…
Question Number 189438 by normans last updated on 16/Mar/23 Answered by som(math1967) last updated on 16/Mar/23 $${construct}\:{FM}\parallel{BE} \\ $$$$\bigtriangleup{AFM}\sim\bigtriangleup{ABE} \\ $$$$\frac{{AM}}{{AE}}=\frac{\mathrm{3}}{\mathrm{3}+\mathrm{5}}=\frac{\mathrm{3}}{\mathrm{8}} \\ $$$$\frac{{AM}}{{ME}}=\frac{\mathrm{3}}{\mathrm{5}} \\ $$$${EO}\parallel{FM}…
Question Number 189421 by normans last updated on 16/Mar/23 Commented by mr W last updated on 16/Mar/23 $${terrible}\:{diagram}:\: \\ $$$${not}\:{clear}\:{if}\:{circle}\:{tangents}\:{the}\:{semi} \\ $$$${circle}. \\ $$$${not}\:{clear}\:{which}\:{angle}\:{is}\:{meant}. \\…
Question Number 189409 by cherokeesay last updated on 15/Mar/23 Answered by HeferH last updated on 15/Mar/23 Commented by HeferH last updated on 15/Mar/23 $$\frac{\mathrm{y}}{\mathrm{4}}\:=\:\frac{\mathrm{6}}{\mathrm{21}} \\…
Question Number 58313 by mr W last updated on 21/Apr/19 Commented by tanmay last updated on 21/Apr/19 Commented by tanmay last updated on 21/Apr/19 $${wait}\:{sir}\:{trying}\:{to}\:{find}\:{x}……
Question Number 123843 by mnjuly1970 last updated on 28/Nov/20 Commented by mnjuly1970 last updated on 28/Nov/20 $${please}\:{solve}\Uparrow\Uparrow \\ $$ Answered by mr W last updated…
Question Number 58282 by behi83417@gmail.com last updated on 20/Apr/19 $$\boldsymbol{\mathrm{A}}\:\boldsymbol{\mathrm{circle}}\:\boldsymbol{\mathrm{tangents}}\:\boldsymbol{\mathrm{to}}\::\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{y}}\:\boldsymbol{\mathrm{axes}}\:\boldsymbol{\mathrm{and}} \\ $$$$\:\:\:\:\boldsymbol{\mathrm{x}}^{\frac{\mathrm{1}}{\mathrm{2}}} +\boldsymbol{\mathrm{y}}^{\frac{\mathrm{1}}{\mathrm{2}}} =\boldsymbol{\mathrm{a}}^{\frac{\mathrm{1}}{\mathrm{2}}} .\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{its}}\:\boldsymbol{\mathrm{radious}}. \\ $$ Answered by mr W last updated on 21/Apr/19…
Question Number 123809 by Dwaipayan Shikari last updated on 28/Nov/20 $$\frac{{log}\mathrm{2}}{\mathrm{1}^{\mathrm{2}} }−\frac{{log}\mathrm{3}}{\mathrm{2}^{\mathrm{2}} }+\frac{{log}\mathrm{4}}{\mathrm{3}^{\mathrm{2}} }−\frac{{log}\mathrm{5}}{\mathrm{4}^{\mathrm{2}} }+… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com