Category: Geometry

Question Number 190856 by TUN last updated on 13/Apr/23 $$GiveMisanypointinABCtriangle$$$$Provethat:MA+MB+MC<AC+BC$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 190745 by TUN last updated on 10/Apr/23 $$GiveMisanypointinABCtriangle.ProvethatMA+MB+MC<AC+BC$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 190644 by cherokeesay last updated on 08/Apr/23 Answered by a.lgnaoui last updated on 09/Apr/23 $$\mathrm{Algebrique}\mathrm{solution}$$$${\mathrm{CercleC}}_1\mathrm{B}:\mathrm{origine}\mathrm{du}\mathrm{Ref}\mathrm{B}(0,0)$$$$\mathrm{et}\:\mathrm{de}\:\mathrm{rayon}\:\mathrm{1}\:\:\:\mathrm{C}_{\mathrm{1}} \left(\mathrm{B},\mathrm{1}\right)\:\left(\:\mathrm{B},\mathrm{E}\right):\mathrm{C}_{\mathrm{1}} \cap\mathrm{C}_{\mathrm{2}} \…

Question Number 190615 by mr W last updated on 07/Apr/23 Commented by mr W last updated on 08/Apr/23 $$1.findratio\frac{a_1}{a}=?suchthattheright$$$$circularconeiscutintotwoparts$$$${with}\:{equal}\:{volume}\:{as}\:{shown}. \…

Question Number 190565 by cherokeesay last updated on 06/Apr/23 Answered by mr W last updated on 06/Apr/23 $$\frac{CB}{\sin x}=\frac{AC}{\sin 30°}\dots \left(i\right)$$$$\frac{\sin (x+30°)}{CB}=\frac{\sin (x+60°)}{DB}\dots \left(ii\right)$$$$\left(i\right)\times \left(ii\right):$$$$\frac{\mathrm{sin}\:\left({x}+\mathrm{30}°\right)}{\mathrm{sin}\:{x}}=\frac{\mathrm{sin}\:\left({x}+\mathrm{60}°\right)}{\mathrm{sin}\:\mathrm{30}°} \…