Category: Geometry

Question Number 190565 by cherokeesay last updated on 06/Apr/23 Answered by mr W last updated on 06/Apr/23 $$\frac{CB}{\sin x}=\frac{AC}{\sin 30°}\dots \left(i\right)$$$$\frac{\sin (x+30°)}{CB}=\frac{\sin (x+60°)}{DB}\dots \left(ii\right)$$$$\left(i\right)\times \left(ii\right):$$$$\frac{\mathrm{sin}\:\left({x}+\mathrm{30}°\right)}{\mathrm{sin}\:{x}}=\frac{\mathrm{sin}\:\left({x}+\mathrm{60}°\right)}{\mathrm{sin}\:\mathrm{30}°} \…

Question Number 124953 by Algoritm last updated on 07/Dec/20 Answered by mr W last updated on 07/Dec/20 $$sayAC=1$$$$\frac{BC}{\sin 30}=\frac{AC}{\sin 50}$$$$\Rightarrow BC=\frac{\sin 30}{\sin 50}$$$${similarly} \…

Question Number 124869 by Algoritm last updated on 06/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 190340 by ajfour last updated on 01/Apr/23 Commented by a.lgnaoui last updated on 01/Apr/23 Commented by a.lgnaoui last updated on 01/Apr/23 Commented by…

Question Number 124722 by I want to learn more last updated on 05/Dec/20 Answered by mr W last updated on 05/Dec/20 Commented by mr W…