Question Number 223619 by Tawa11 last updated on 01/Aug/25 Answered by Frix last updated on 01/Aug/25 $$\mid{C}_{\mathrm{1}} {C}_{\mathrm{2}} \mid=\sqrt{\mathrm{2}} \\ $$$$\Rightarrow\:{C}_{\mathrm{1}} ,\:{C}_{\mathrm{2}} \:\mathrm{form}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with}\:\mathrm{each}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{intersection}\:\mathrm{points}\:\mathrm{with}…
Question Number 223595 by ajfour last updated on 31/Jul/25 Commented by ajfour last updated on 31/Jul/25 $$\:\:\:\:\:\:\:\:\:\:{Given}\:\theta.\:{Find}\:\phi. \\ $$ Answered by mr W last updated…
Question Number 223544 by ajfour last updated on 29/Jul/25 Commented by ajfour last updated on 29/Jul/25 $${If}\:\mathrm{2}{R}\theta=\mathrm{2}\pi{r},\:{find}\:{R}/{r}\:{for}\:{h}=\mathrm{0}. \\ $$ Answered by mr W last updated…
Question Number 223523 by Nicholas666 last updated on 27/Jul/25 Commented by Nicholas666 last updated on 27/Jul/25 $$\:\:\boldsymbol{\mathrm{how}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{problem}}\:?\: \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 223490 by mr W last updated on 26/Jul/25 Commented by Ghisom last updated on 27/Jul/25 $$\frac{\mathrm{1}}{\mathrm{2}}{a}\left({a}+{b}\right)−\frac{\mathrm{1}}{\mathrm{2}}{a}\left({a}−{b}\right)={ab}=\mathrm{77}{cm}^{\mathrm{2}} \\ $$ Commented by mr W last…
Question Number 223449 by ajfour last updated on 25/Jul/25 Answered by ajfour last updated on 26/Jul/25 $$\:\:\:\sqrt{\mathrm{1}−\theta^{\mathrm{2}} }=\frac{\mathrm{sin}\:\left(\phi−\theta\right)}{\mathrm{sin}\:\phi} \\ $$$${Wow}!\:\:\:\:\:\:{arc}\:{CD}=\:{line}\:{AB} \\ $$$$ \\ $$$$\bullet\:{Find}\:{CT}/{AO}={t}/{R}\:\:{in}\:{terms}\:{of}\:\theta. \\…
Question Number 223383 by mr W last updated on 23/Jul/25 Commented by Frix last updated on 23/Jul/25 $$\mathrm{I}\:\mathrm{guess}\:\mathrm{it}'\mathrm{s}\:\mathrm{66} \\ $$ Commented by Frix last updated…
Question Number 223301 by cemoosky last updated on 21/Jul/25 Answered by som(math1967) last updated on 21/Jul/25 $$\:\:\:{Ar}\:{of}\:{PQRK}=\mathrm{3}×\bigtriangleup{PSK} \\ $$$$\:{area}\:{of}\bigtriangleup{PSK}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{15sin}\:\mathrm{30}×\mathrm{15cos}\:\mathrm{30} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{225}\sqrt{\mathrm{3}}}{\mathrm{4}}{cm}^{\mathrm{2}} \\ $$$$\:{area}\:{of}\:{PQRK}=\mathrm{3}×\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{225}\sqrt{\mathrm{3}}}{\mathrm{4}} \\ $$$$=\frac{\mathrm{675}\sqrt{\mathrm{3}}}{\mathrm{8}}{cm}^{\mathrm{2}}…
Question Number 223315 by sonukgindia last updated on 21/Jul/25 Commented by fantastic last updated on 21/Jul/25 $${Those}\:{two}\:{square}\:{means}\:{angle}?? \\ $$ Commented by fantastic last updated on…
Question Number 223286 by mehdee7396 last updated on 20/Jul/25 $${OC}=\mathrm{4}.\mathrm{5}\:\:\:\&\:\:{EF}=\mathrm{2}\:\:\&\:\:{D}\overset{\frown} {{E}}={E}\overset{\frown} {{C}}\:\:\&\:\:{AC}=\mathrm{2}{AF}\Rightarrow{AB}=? \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\Downarrow\Downarrow\Downarrow \\ $$ Commented by fantastic last updated on 20/Jul/25 $$\mathrm{13}?? \\…