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Question Number 214100 by ajfour last updated on 28/Nov/24 Answered by ajfour last updated on 29/Nov/24 Commented by ajfour last updated on 29/Nov/24 $$\mathrm{sin}\:\alpha=\frac{{a}}{\mathrm{2}{b}+{a}}=\frac{\mathrm{1}}{\mathrm{2}{s}+\mathrm{1}}\:\:\:\forall\:\:{s}=\frac{{b}}{{a}},\:{t}=\frac{{r}}{{a}} \…
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