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Category: Geometry

Question-120946

Question Number 120946 by mnjuly1970 last updated on 04/Nov/20 Answered by Jamshidbek2311 last updated on 04/Nov/20 $$\frac{{sin}\beta}{{sin}\mathrm{20}°}=\frac{{sin}\left(\mathrm{110}°−\beta\right)}{{sin}\mathrm{10}°}\:\Rightarrow\:\beta=\mathrm{80}° \\ $$$$ \\ $$ Terms of Service Privacy…

Question-186408

Question Number 186408 by normans last updated on 04/Feb/23 Answered by mr W last updated on 04/Feb/23 $${R}={radius}\:{of}\:{big}\:{circle} \\ $$$${r}={radius}\:{of}\:{small}\:{circles} \\ $$$$\left({R}−{r}\right)^{\mathrm{2}} =\left(\mathrm{3}{r}\right)^{\mathrm{2}} +{r}^{\mathrm{2}} \\…