Question Number 186298 by TUN last updated on 03/Feb/23 Answered by a.lgnaoui last updated on 05/Feb/23 $$\bigtriangleup{ABC}\:\::\:\mathrm{6}+\mathrm{36}+{x}+{y}+\mathrm{z}+\mathrm{12}=\mathrm{180} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}+{y}+\mathrm{z}=\mathrm{126} \\ $$$$\:\bigtriangleup\mathrm{ACD}:\:\:\frac{\mathrm{sin}\:{x}}{\mathrm{AD}}=\frac{\mathrm{sin}\:\mathrm{y}}{\mathrm{CD}}=\frac{\mathrm{sin}\:\left(\mathrm{x}+\mathrm{y}\right)}{\mathrm{AC}}\left(\mathrm{1}\right) \\ $$$$\bigtriangleup\mathrm{ABC}\:\:\:\frac{\mathrm{sin}\:\left(\mathrm{y}+\mathrm{12}\right)}{\mathrm{BC}}=\frac{\mathrm{sin}\:\mathrm{42}}{\mathrm{AC}}\left(\mathrm{2}\right) \\ $$$$\:\left(\mathrm{1}\right)\Rightarrow\mathrm{sin}\:{y}=\frac{{CD}}{{AD}}\mathrm{sin}\:\mathrm{x}…
Question Number 186293 by ajfour last updated on 03/Feb/23 Commented by ajfour last updated on 03/Feb/23 $${But}\:{if}\:{R}\:{be}\:{unique},\:{still}\:{find}\:{R}. \\ $$ Commented by mr W last updated…
Question Number 186282 by Mingma last updated on 03/Feb/23 Answered by mr W last updated on 03/Feb/23 Commented by mr W last updated on 03/Feb/23…
Question Number 186271 by cherokeesay last updated on 02/Feb/23 Answered by HeferH last updated on 02/Feb/23 Commented by HeferH last updated on 02/Feb/23 $${x}\:+\:\frac{{x}}{\:\sqrt{\mathrm{3}}}\:+\:\frac{\mathrm{2}}{\:\sqrt{\mathrm{3}}}\left({x}\:+\:{x}\sqrt{\mathrm{3}}\right)\:=\:\mathrm{6} \\…
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Question Number 186236 by ajfour last updated on 02/Feb/23 Answered by a.lgnaoui last updated on 02/Feb/23 $$\mathrm{1} \\ $$ Commented by ajfour last updated on…
Question Number 120676 by I want to learn more last updated on 01/Nov/20 Commented by som(math1967) last updated on 02/Nov/20 $$\mathrm{BC}+\mathrm{AC}−\mathrm{AB} \\ $$$$=\mathrm{5}+\mathrm{6}−\mathrm{3}=\mathrm{8unit} \\ $$…
Question Number 186172 by normans last updated on 01/Feb/23 Answered by HeferH last updated on 01/Feb/23 $$\cancel{\frac{\mathrm{231}}{\mathrm{2}}\:?} \\ $$$$\mathrm{147}\: \\ $$ Answered by mr W…
Question Number 186165 by ajfour last updated on 01/Feb/23 Answered by mr W last updated on 01/Feb/23 $$\frac{{c}}{{x}}=\frac{{x}−\mathrm{1}}{\:\sqrt{{x}^{\mathrm{2}} −\left({x}−\mathrm{1}\right)^{\mathrm{2}} }}=\frac{{x}−\mathrm{1}}{\:\sqrt{\mathrm{2}{x}−\mathrm{1}}} \\ $$$${x}\left({x}−\mathrm{1}\right)={c}\sqrt{\mathrm{2}{x}−\mathrm{1}} \\ $$$${x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{3}}…
Question Number 186141 by Mingma last updated on 01/Feb/23 Commented by mr W last updated on 01/Feb/23 $$\frac{{x}}{\mathrm{8}}=\frac{\mathrm{2}}{{x}}\:\Rightarrow{x}=\mathrm{4} \\ $$ Terms of Service Privacy Policy…