Question Number 186143 by Rupesh123 last updated on 01/Feb/23 Answered by HeferH last updated on 01/Feb/23 $$\mathrm{2}{x}\:+\:\mathrm{24}°\:=\:\mathrm{180}° \\ $$$${x}\:=\:\mathrm{78}° \\ $$ Commented by HeferH last…
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Question Number 55044 by behi83417@gmail.com last updated on 16/Feb/19 Commented by behi83417@gmail.com last updated on 16/Feb/19 $${as}\:{shown}\:{in}\:{picture}: \\ $$$${find}\:{locus}\:{of}\:{centroid}\:{of}\:{triangle}: \\ $$$$\left.\mathrm{1}\right){when}:\boldsymbol{{B}}\:{and}\:\boldsymbol{{C}},{are}\:{fixed}\:{and}:\boldsymbol{{A}}\:{moves} \\ $$$${on}\:{the}\:{circle}'{s}\:\:{perimeter}. \\ $$$$\left.\mathrm{2}\right)\boldsymbol{{C}},{is}\:{fixed}\:{and}\:\boldsymbol{{A}}\:{and}\:\boldsymbol{{B}}\:\:{are}\:{moving}\:{on}…
Question Number 186111 by Rupesh123 last updated on 01/Feb/23 Commented by Rupesh123 last updated on 01/Feb/23 A right angle is rotated and translated as shown in the diagram Commented by mr W last updated on 01/Feb/23…
Question Number 120569 by prakash jain last updated on 01/Nov/20 Commented by prakash jain last updated on 01/Nov/20 $$\mathrm{There}\:\mathrm{are}\:\mathrm{4}\:\mathrm{equilateral}\:\mathrm{triangles}\:\mathrm{in} \\ $$$$\mathrm{figure}.\:\mathrm{Find}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{colored}\:\mathrm{region} \\ $$$$\mathrm{to}\:\mathrm{the}\:\mathrm{largest}\:\mathrm{triangle} \\ $$…
Question Number 186079 by TUN last updated on 31/Jan/23 Answered by a.lgnaoui last updated on 01/Feb/23 $$\bigtriangleup{ABD}\:\:\:{et}\:\bigtriangleup\:{ACD}\:\:\:{AD}:{cote}\:{commun} \\ $$$$\bigtriangleup{ABD}:\:\: \\ $$$$\frac{\mathrm{sin}\:\mathrm{46}}{\mathrm{BD}}\:=\frac{\mathrm{sin}\:\mathrm{X}}{\mathrm{AD}}\:\:\left(\mathrm{1}\right) \\ $$$$\bigtriangleup{ACD} \\ $$$$\frac{\mathrm{sin}\:\mathrm{12}}{\mathrm{CD}}=\frac{\mathrm{sin}\:\mathrm{62}}{\mathrm{AD}}\:\:\left(\mathrm{2}\right)…
Question Number 186069 by TUN last updated on 31/Jan/23 Answered by HeferH last updated on 31/Jan/23 $$\alpha=\mathrm{10}° \\ $$ Commented by HeferH last updated on…
Question Number 54991 by Tawa1 last updated on 15/Feb/19 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{roots}\:\mathrm{of}:\:\:\:\:\:\:\mathrm{z}^{\mathrm{4}} \:+\:\mathrm{16i}\:\:=\:\:\mathrm{0} \\ $$ Commented by maxmathsup by imad last updated on 15/Feb/19 $${z}^{\mathrm{4}} \:+\mathrm{16}{i}\:=\mathrm{0}\:\Leftrightarrow\:{z}^{\mathrm{4}} =−\mathrm{16}{i}\:\:\:\:\:{let}\:{z}\:={r}\:{e}^{{i}\theta}…
Question Number 185993 by ajfour last updated on 30/Jan/23 Answered by mr W last updated on 30/Jan/23 Commented by mr W last updated on 30/Jan/23…
Question Number 185953 by ajfour last updated on 30/Jan/23 Commented by ajfour last updated on 30/Jan/23 $${Would}\:{it}\:{be}\:{r}\approx\mathrm{0}.\mathrm{432}\:? \\ $$ Commented by TUN last updated on…