Question Number 184955 by mnjuly1970 last updated on 14/Jan/23 Answered by HeferH last updated on 14/Jan/23 Commented by HeferH last updated on 14/Jan/23 $$\:{A}_{{OAB}} \:=\:\frac{{a}\centerdot\mathrm{6}}{\mathrm{2}}\:=\:\frac{\pi}{\mathrm{6}}\:\centerdot\:\mathrm{6}\:\centerdot\:\frac{\mathrm{6}}{\mathrm{2}}\:=\:\mathrm{3}\pi\:\:\:\:\:\ast\left({a}\:=\:{arc}\right)\:…
Question Number 53792 by behi83417@gmail.com last updated on 25/Jan/19 Commented by behi83417@gmail.com last updated on 25/Jan/19 $${A}\overset{\blacktriangle} {{B}C},{equilateral}\:{with}:{AB}=\mathrm{1}. \\ $$$${circle}\:{with}\:{radius}:\:\boldsymbol{{r}}=\frac{\mathrm{1}}{\mathrm{2}\pi},\:{tangents}\:{to} \\ $$$${AC}\:{and}\:{AB}\:{at}:\:{D},{E}. \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{min}}\:\boldsymbol{\mathrm{distance}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{circle}}\:\boldsymbol{\mathrm{from}}\:\boldsymbol{\mathrm{vertices}} \\…
Question Number 184822 by mnjuly1970 last updated on 12/Jan/23 Answered by mr W last updated on 12/Jan/23 Commented by mr W last updated on 12/Jan/23…
Question Number 53727 by Tawa1 last updated on 25/Jan/19 Answered by Kunal12588 last updated on 25/Jan/19 $${just}\:{trying} \\ $$$${T}_{\mathrm{1}} ,{T}_{\mathrm{2}} ,{T}_{\mathrm{3}} ,{T}_{\mathrm{4}} −{lower}\:{cables} \\ $$$${T}_{\mathrm{1}}…
Question Number 53664 by ajfour last updated on 24/Jan/19 Commented by ajfour last updated on 24/Jan/19 $${The}\:{bases}\:{of}\:{the}\:{cones}\:{touch}\:{each} \\ $$$${other}\:{pairwise}.\:{Find}\:{the}\:{radius}\:{of} \\ $$$${the}\:{sphere}\:{tangent}\:{to}\:{all}\:{the}\:{three} \\ $$$${cones}\:{and}\:{to}\:{the}\:{plane}\:{passing} \\ $$$${through}\:{their}\:{vertices}.\:\left({semi}-{vertical}\right.…
Question Number 184724 by HeferH last updated on 10/Jan/23 Commented by HeferH last updated on 10/Jan/23 $${if}\:{AB}\:=\:{a},\:{AE}\:=\:{b}\:{and}\:{MC}\:=\:{c} \\ $$$$\:{find}\:{MD}\:{in}\:{terms}\:{if}\:{a},{b}\:{and}\:{c}\: \\ $$ Terms of Service Privacy…
Question Number 119187 by mr W last updated on 22/Oct/20 Commented by mr W last updated on 22/Oct/20 $${Question}\:{from}\:{Mind}\:{Your}\:{Decisions}. \\ $$ Commented by benjo_mathlover last…
Question Number 184718 by sonukgindia last updated on 10/Jan/23 Answered by HeferH last updated on 10/Jan/23 $${Let}\:\mathrm{2}{a}\:{be}\:{the}\:{side}\:{of}\:{those}\:{squares}\:{and}\:{x}\:{the}\: \\ $$$${larger}\:{side}\:{of}\:{the}\:{yellow}\:{triangle}.\: \\ $$$$\:{A}_{{rect}} =\:\mathrm{2}{a}\:\centerdot\:\mathrm{4}{a}\:=\mathrm{8}{a}^{\mathrm{2}} \\ $$$$\:{by}\:{product}\:{of}\:{chords}: \\…
Question Number 184719 by sonukgindia last updated on 10/Jan/23 Answered by mr W last updated on 11/Jan/23 Commented by mr W last updated on 11/Jan/23…
Question Number 53570 by ajfour last updated on 23/Jan/19 Commented by ajfour last updated on 23/Jan/19 $${Regular}\:{pentagon}\:{side}\:{a}.\:{Find}\:{the} \\ $$$${central}\:{uncoloured}\:{area}. \\ $$ Commented by tanmay.chaudhury50@gmail.com last…