Question Number 52012 by adilmalik78623@gmail.com last updated on 02/Jan/19 Commented by mr W last updated on 02/Jan/19 Commented by tanmay.chaudhury50@gmail.com last updated on 02/Jan/19 $${pointB}\left(\mathrm{3}{r}+\mathrm{2},\mathrm{4}{r}+\mathrm{3},\mathrm{5}{r}+\mathrm{4}\right)\:{be}\:{the}\:{foot}\:{of}\:{perpendicular}…
Question Number 183071 by HeferH last updated on 19/Dec/22 Answered by manolex last updated on 20/Dec/22 Commented by manolex last updated on 20/Dec/22 $${x}=\mathrm{15}. \\…
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Question Number 51973 by ajfour last updated on 01/Jan/19 Commented by ajfour last updated on 02/Jan/19 $${AB}\:=\:{PQ}\:=\:{c}\:\:,\:{BC}\:=\:{QR}\:=\:{a} \\ $$$${Find}\:{maximum}\:{area}\:{of}\:{hexagon} \\ $$$${DEFGHID}.\:\: \\ $$ Terms of…
Question Number 117480 by I want to learn more last updated on 12/Oct/20 Commented by Tawa11 last updated on 15/Sep/21 $$\mathrm{nice} \\ $$ Answered by…
Question Number 117481 by I want to learn more last updated on 12/Oct/20 Answered by mr W last updated on 12/Oct/20 $${let}\:{AC}=\mathrm{1} \\ $$$$\frac{{OC}}{\mathrm{sin}\:\mathrm{20}}=\frac{{AC}}{\mathrm{sin}\:\left(\mathrm{10}+\mathrm{20}\right)} \\…
Question Number 51942 by mr W last updated on 01/Jan/19 Commented by mr W last updated on 01/Jan/19 $${Find}\:{the}\:{sum}\:{of}\:{all}\:{corner}\:{angles} \\ $$$${of}\:{a}\:{n}−{corner}\:{star}. \\ $$$$\alpha_{\mathrm{1}} +\alpha_{\mathrm{2}} +\alpha_{\mathrm{3}}…
Question Number 183008 by mr W last updated on 18/Dec/22 Commented by mr W last updated on 18/Dec/22 $$\mid{OA}\mid={a},\:\mid{OB}\mid={b},\:\mid{OC}\mid={c} \\ $$$${find}\:{the}\:{equation}\:{of}\:{the}\:{incribed} \\ $$$${circle}\:{and}\:{that}\:{of}\:{the}\:{circumcircle}. \\ $$…
Question Number 51911 by munnabhai455111@gmail.com last updated on 01/Jan/19 Commented by munnabhai455111@gmail.com last updated on 01/Jan/19 help soon please! Commented by prakash jain last updated on 01/Jan/19…
Question Number 51905 by Tawa1 last updated on 01/Jan/19 $$\mathrm{If}\:\:\:\mathrm{p}\:\:=\:\:\mathrm{cos}\:\theta\:+\:\mathrm{i}\:\mathrm{sin}\theta\:\:\:\:\:\:\:\:\:\:\:\mathrm{and}\:\:\:\:\:\:\:\mathrm{q}\:\:=\:\:\mathrm{cos}\:\phi\:+\:\mathrm{i}\:\mathrm{sin}\:\phi \\ $$$$\mathrm{Show}\:\mathrm{that}: \\ $$$$\left(\mathrm{i}\right)\:\:\:\:\:\:\frac{\mathrm{p}\:−\:\mathrm{q}}{\mathrm{p}\:+\:\mathrm{q}}\:\:=\:\:\mathrm{i}\:\mathrm{tan}\:\left(\frac{\theta\:−\:\phi}{\mathrm{2}}\right) \\ $$$$\left(\mathrm{ii}\right)\:\:\:\frac{\left(\mathrm{p}\:+\:\mathrm{q}\right)\left(\mathrm{pq}\:−\:\mathrm{1}\right)}{\left(\mathrm{p}\:−\:\mathrm{q}\right)\left(\mathrm{pq}\:+\:\mathrm{1}\right)}\:\:=\:\:\frac{\mathrm{sin}\:\theta\:+\:\mathrm{sin}\:\phi}{\mathrm{sin}\:\theta\:−\:\mathrm{sin}\:\phi} \\ $$ Answered by Kunal12588 last updated on 01/Jan/19…