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Category: Integration

sinx-3-dx-

Question Number 124906 by Mammadli last updated on 06/Dec/20 $$\int\boldsymbol{{sinx}}^{\mathrm{3}} \boldsymbol{{dx}}=? \\ $$ Commented by Dwaipayan Shikari last updated on 06/Dec/20 $$\int{sinx}^{\mathrm{3}} {dx}\:\:\:\:\:\:\:\:\:\: \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}{i}}\int{e}^{{ix}^{\mathrm{3}}…

Question-124903

Question Number 124903 by Algoritm last updated on 06/Dec/20 Answered by MJS_new last updated on 06/Dec/20 $$\mathrm{just}\:\mathrm{decompose}\:\mathrm{and}\:\mathrm{solve},\:\mathrm{no}\:\mathrm{special} \\ $$$$\mathrm{knowledge}\:\mathrm{necessary}.\:\mathrm{the}\:\mathrm{answer}\:\mathrm{is}: \\ $$$$\frac{{x}−\mathrm{1}}{\mathrm{2}\left({x}^{\mathrm{2}} +\mathrm{1}\right)}+\frac{\mathrm{1}}{\mathrm{4}}\mathrm{ln}\:\left({x}^{\mathrm{2}} +\mathrm{1}\right)\:−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\:\mid{x}+\mathrm{1}\mid\:+{C} \\ $$$$\mathrm{now}\:\mathrm{try}\:\mathrm{to}\:\mathrm{reach}\:\mathrm{this}\:\mathrm{for}\:\mathrm{yourself}…

nice-calculus-evaluate-2-1-x-1-2-x-dx-0-1-ln-x-dx-x-fractional-part-

Question Number 124887 by mnjuly1970 last updated on 06/Dec/20 $$\:\:\:\:\:…{nice}\:\:{calculus}.. \\ $$$$\:\:\:{evaluate}\:: \\ $$$$\:\:\mathrm{2}\int_{\mathrm{1}} ^{\:\infty} \left(\frac{\left\{{x}\right\}−\frac{\mathrm{1}}{\mathrm{2}}}{{x}}\right){dx}−\int_{\mathrm{0}} ^{\:\mathrm{1}} {ln}\left(\Gamma\left({x}\right)\right){dx}=??? \\ $$$$\left\{{x}\right\}:\:{fractional}\:{part}… \\ $$ Answered by Dwaipayan…

e-x-1-sin-x-1-cos-x-dx-

Question Number 59344 by rahul 19 last updated on 08/May/19 $$\int\:{e}^{{x}} \left(\frac{\mathrm{1}−\mathrm{sin}\:{x}}{\mathrm{1}−\mathrm{cos}\:{x}}\right){dx}\:=\:? \\ $$ Answered by MJS last updated on 08/May/19 $$\mathrm{the}\:\mathrm{trick}\:\mathrm{is}\:\mathrm{this}: \\ $$$$\frac{\mathrm{1}−\mathrm{sin}\:{x}}{\mathrm{1}−\mathrm{cos}\:{x}}=\frac{\mathrm{1}}{\mathrm{1}−\mathrm{cos}\:{x}}−\frac{\mathrm{sin}\:{x}}{\mathrm{1}−\mathrm{cos}\:{x}}=\frac{\mathrm{1}}{\mathrm{2sin}^{\mathrm{2}} \:\frac{{x}}{\mathrm{2}}}−\frac{\mathrm{1}}{\mathrm{tan}\:\frac{{x}}{\mathrm{2}}}=…