Category: Integration

Question Number 191303 by Mingma last updated on 22/Apr/23 Answered by mahdipoor last updated on 22/Apr/23 $$\int f\left(x\right)=\int {xf}^{{}^{\prime }}\left(x\right)-\sqrt{2x-x^2}=[xf\left(x\right)-\int f\left(x\right)]-\int \sqrt{2x-x^2}$$$$\Rightarrow\int_{\mathrm{0}} ^{\:\mathrm{1}} {f}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{2}}\left[{xf}\left({x}\right)\right]_{\mathrm{0}} ^{\mathrm{1}}…

Question Number 60170 by necx1 last updated on 18/May/19 $$\int x\sec {}^{3}xdx$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 191188 by cortano12 last updated on 20/Apr/23 $$\int \sqrt[4]{\frac{2-\mathrm{x}}{1-\mathrm{x}}}\mathrm{dx}=?$$ Answered by mehdee42 last updated on 20/Apr/23 $$\sqrt[{\mathrm{4}}]{\frac{\mathrm{2}−{x}}{\mathrm{1}−{x}}}={u}\Rightarrow{x}=\frac{{u}^{\mathrm{4}} −\mathrm{2}}{{u}^{\mathrm{4}} −\mathrm{1}}\Rightarrow{dx}=\frac{\mathrm{4}{u}^{\mathrm{3}} }{\left({u}^{\mathrm{4}} −\mathrm{1}\right)^{\mathrm{2}} \:}\:{du}…

Question Number 60050 by maxmathsup by imad last updated on 17/May/19 $$calculate{\int }_0^1(x^3-2)\sqrt{x^2+3}dx$$ Commented by maxmathsup by imad last updated…

Question Number 60027 by aliesam last updated on 17/May/19 $$\int x^{i}dx=?$$ Answered by MJS last updated on 17/May/19 $$\int x^{\mathrm{i}}dx=\frac{1}{1+\mathrm{i}}{x}^{1+\mathrm{i}}+C=\frac{1-\mathrm{i}}{2}{x}^{1+\mathrm{i}}$$…