Question Number 127605 by pticantor last updated on 31/Dec/20 $${find}\:{arg}\left({z}\right) \\ $$$${where}\:\boldsymbol{{z}}=\mathrm{1}+\boldsymbol{{cos}}\alpha+{icos}\beta \\ $$ Answered by MJS_new last updated on 31/Dec/20 $$\mathrm{arg}\:\left(\mathrm{1}+\mathrm{cos}\:\alpha\:+\mathrm{i}\:\mathrm{cos}\:\beta\right)\:= \\ $$$$=\frac{\pi}{\mathrm{2}}\mathrm{sign}\:\left(\mathrm{cos}\:\beta\right)\:−\mathrm{arctan}\:\frac{\mathrm{1}+\mathrm{cos}\:\alpha}{\mathrm{cos}\:\beta} \\…
Question Number 62056 by maxmathsup by imad last updated on 14/Jun/19 $$\left.\mathrm{1}\right)\:{calculate}\:{I}\:=\int{ln}\left(\mathrm{1}+{ix}^{\mathrm{2}} \right){dx}\:{and}\:{J}\:=\:\int{ln}\left(\mathrm{1}−{ix}^{\mathrm{2}} \right){dx} \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{A}\:=\int\:{ln}\left(\mathrm{1}+{x}^{\mathrm{4}} \right){dx}\:. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 127587 by bramlexs22 last updated on 31/Dec/20 Answered by ebi last updated on 31/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 127575 by Ar Brandon last updated on 30/Dec/20 $$\mathrm{I}_{\mathrm{n}} =\int_{\mathrm{0}} ^{\mathrm{1}} \left(\mathrm{1}−\mathrm{t}^{\mathrm{2}} \right)^{\mathrm{n}} \mathrm{dt} \\ $$ Answered by Ar Brandon last updated on…
Question Number 127543 by Ar Brandon last updated on 30/Dec/20 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{x}^{\mathrm{2021}} }{\mathrm{e}^{\mathrm{x}} −\mathrm{1}}\mathrm{dx} \\ $$ Answered by Dwaipayan Shikari last updated on 30/Dec/20…
Question Number 127539 by mnjuly1970 last updated on 30/Dec/20 $$\:\:\:\:\:\:\:\:\:\:\:\:\:…{nice}\:\:\:{calculus}… \\ $$$$\:\:\:{evaluate}\:::: \\ $$$$\:\:\:\:\:\Phi=\int_{\mathrm{0}} ^{\:\infty} \frac{{ln}\left({x}\right)}{\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{3}} }\:{dx}=? \\ $$$$ \\ $$ Answered by Lordose…
Question Number 62001 by maxmathsup by imad last updated on 13/Jun/19 $${find}\:\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \:\:\:\frac{{x}^{\mathrm{2}} }{\mathrm{1}−{cos}\left({x}\right)}{dx}\: \\ $$ Commented by maxmathsup by imad last updated on…
Question Number 62000 by maxmathsup by imad last updated on 13/Jun/19 $${calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:{ln}\left(\mathrm{1}+{x}\right){ln}^{\mathrm{2}} \left(\mathrm{1}−{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 127528 by bramlexs22 last updated on 30/Dec/20 $$\:\int_{\mathrm{0}} ^{\:\pi/\mathrm{4}} \frac{\mathrm{sin}\:\mathrm{x}}{\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}}\:\mathrm{dx}\:=?\: \\ $$ Answered by liberty last updated on 30/Dec/20 $$\:{Let}\:{L}\:=\:\int_{\mathrm{0}} ^{\:\pi/\mathrm{4}} \frac{\mathrm{sin}\:{x}}{\mathrm{sin}\:{x}+\mathrm{cos}\:{x}}\:{dx}\: \\…
Question Number 61986 by necx1 last updated on 13/Jun/19 $${Find}\:{the}\:{area}\:{bounded}\:{by}\:{y}\left({x}+\mathrm{2}\right)={x}^{\mathrm{4}} , \\ $$$${x}=\mathrm{0},{y}=\mathrm{0}\:{and}\:{x}=\mathrm{3} \\ $$ Answered by mr W last updated on 13/Jun/19 $${y}=\frac{{x}^{\mathrm{4}} }{{x}+\mathrm{2}}…