Question Number 125187 by bemath last updated on 08/Dec/20
Question Number 59647 by aliesam last updated on 12/May/19 Commented by Mr X pcx last updated on 13/May/19 $${I}\:=\:\int_{\mathrm{0}} ^{\pi} \:\:\frac{{cosx}\:{e}^{\mid{sinx}\mid} }{\mathrm{1}+{e}^{{tanx}} }\:{dx}\:+\int_{\pi} ^{\mathrm{2}\pi} \:\frac{{cosx}\:{e}^{\mid{sinx}\mid}…
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