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Category: Integration

Question-190841

Question Number 190841 by Rupesh123 last updated on 12/Apr/23 Answered by ARUNG_Brandon_MBU last updated on 12/Apr/23 I=0πxdx1+cosαsinx=0ππx1+cosαsinxdx$$\:\:\:=\frac{\mathrm{1}}{\mathrm{2}}\int_{\mathrm{0}} ^{\pi} \frac{\pi}{\mathrm{1}+\mathrm{cos}\alpha\mathrm{sin}{x}}{dx}=\frac{\mathrm{1}}{\mathrm{2}}\int_{\mathrm{0}}…