Menu Close

Category: Integration

Question-190371

Question Number 190371 by TUN last updated on 02/Apr/23 Answered by qaz last updated on 02/Apr/23 $$\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{sin}\:\left({ln}\frac{\mathrm{1}}{{x}}\right)\frac{{x}^{{b}} −{x}^{{a}} }{{lnx}}{dx}=\int_{−\infty} ^{\mathrm{0}} \mathrm{sin}\:\left(−{u}\right)\centerdot\frac{{e}^{{ub}} −{e}^{{ua}} }{{u}}{e}^{{u}}…