Question Number 189323 by mnjuly1970 last updated on 14/Mar/23 Answered by witcher3 last updated on 14/Mar/23 $$\Leftrightarrow\Sigma\frac{\Gamma\left(\mathrm{n}\right)\Gamma\left(\mathrm{n}\right)}{\Gamma\left(\mathrm{2n}\right).\mathrm{2}^{−\mathrm{n}} }=\underset{\mathrm{n}\geqslant\mathrm{1}} {\sum}\frac{\beta\left(\mathrm{n},\mathrm{n}\right)}{\mathrm{2}^{−\mathrm{n}} } \\ $$$$=\underset{\mathrm{n}\geqslant\mathrm{1}} {\sum}\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{x}^{\mathrm{n}−\mathrm{1}}…
Question Number 58250 by Tawa1 last updated on 20/Apr/19 $$\int_{\:\mathrm{0}} ^{\:\mathrm{1}} \:\:\left(\frac{\mathrm{3x}^{\mathrm{3}} \:−\:\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{2x}\:−\:\mathrm{4}}{\:\sqrt{\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{3x}\:+\:\mathrm{2}}}\right)\:\mathrm{dx} \\ $$ Answered by MJS last updated on 21/Apr/19 $$\underset{\mathrm{0}}…
Question Number 58249 by tanmay last updated on 20/Apr/19 $$\overset{} {{I}}_{{n}} =\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {cos}^{{n}} {xcos}\left({nx}\right){dx} \\ $$$${then}\:{show}\:{that}\:{I}_{\mathrm{1}} ,{I}_{\mathrm{2}} ,{I}_{\mathrm{3}} ….{are}\:{in}\:{G}.{P} \\ $$ Terms of Service…
Question Number 58240 by salaw2000 last updated on 20/Apr/19 $$\mathrm{i}=\int\mathrm{dx}/\left(\mathrm{ax}^{\mathrm{2}} +\mathrm{bx}+\mathrm{c}\right)^{\frac{\mathrm{3}}{\mathrm{2}}} \\ $$ Commented by maxmathsup by imad last updated on 21/Apr/19 $${let}\:{I}\:=\int\:\:\frac{{dx}}{\left({ax}^{\mathrm{2}} \:+{bx}\:+{c}\right)^{\frac{\mathrm{3}}{\mathrm{2}}} }\:\:{let}\:{p}\left({x}\right)={ax}^{\mathrm{2}}…
Question Number 58238 by Tawa1 last updated on 20/Apr/19 $$\int_{\:\mathrm{0}} ^{\:\mathrm{1}} \:\:\left(\frac{\mathrm{3}\boldsymbol{\mathrm{x}}^{\mathrm{3}} \:−\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} \:+\:\mathrm{2}\boldsymbol{\mathrm{x}}\:−\:\mathrm{4}}{\:\sqrt{\boldsymbol{\mathrm{x}}^{\mathrm{2}} \:−\:\mathrm{3}\boldsymbol{\mathrm{x}}\:+\:\mathrm{2}}}\right)\:\:\boldsymbol{\mathrm{dx}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 123768 by oustmuchiya@gmail.com last updated on 28/Nov/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 123769 by oustmuchiya@gmail.com last updated on 28/Nov/20 Commented by oustmuchiya@gmail.com last updated on 17/Dec/20 $$ \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 123764 by mnjuly1970 last updated on 28/Nov/20 $$\:\:\:\:\:\:\:\:\:\:\:\:….\:{advanced}\:\:{calculus}\:… \\ $$$$\:\:\:\:\:\:\:{prove}\:\:{that}:::: \\ $$$$\:\:\:\:\:\:\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left\{\frac{\zeta\left(\mathrm{2}{n}+\mathrm{1}\right)}{\mathrm{4}^{{n}\:} \:\left(\mathrm{2}{n}+\mathrm{1}\right)}\right\}={ln}\left(\mathrm{2}\right)−\gamma \\ $$$$\:\:\:\:\:\:\:\:\gamma::\:\:{euler}−{mascheroni} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{constant} \\ $$ Answered by…
Question Number 123767 by oustmuchiya@gmail.com last updated on 28/Nov/20 Answered by physicstutes last updated on 28/Nov/20 $$\:\:\boldsymbol{\mathrm{s}}\:=\:\mathrm{2}{t}\:+\:\mathrm{3}\:\mathrm{sin}\:\mathrm{2}{t} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{Initiat}\:\mathrm{position}\:\mathrm{occurs}\:\mathrm{at}\:{t}\:=\:\mathrm{0}\:\mathrm{s} \\ $$$$\Rightarrow\:\boldsymbol{\mathrm{s}}_{\mathrm{0}} \:=\:\mathrm{2}\left(\mathrm{0}\right)\:+\:\mathrm{3}\:\mathrm{sin}\:\mathrm{2}\left(\mathrm{0}\right) \\ $$$$\:\:\:\:\:\:\boldsymbol{\mathrm{s}}_{\mathrm{0}} \:=\:\mathrm{0}\:\mathrm{m}…
Question Number 189293 by Rupesh123 last updated on 14/Mar/23 Answered by Sutrisno last updated on 14/Mar/23 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{{sin}^{\mathrm{2}} {x}}{\frac{\mathrm{1}}{{sin}^{\mathrm{2}} {x}}+\frac{{cos}^{\mathrm{2}} {x}}{{sin}^{\mathrm{2}} {x}}}{dx} \\ $$$$\int_{\mathrm{0}}…