Category: Integration

Question Number 213724 by Spillover last updated on 14/Nov/24 Commented by TonyCWX08 last updated on 16/Nov/24 $$Iseewhoyouare\dots$$ Terms of Service Privacy Policy Contact:…

Question Number 213662 by Spillover last updated on 13/Nov/24 Answered by mathmax last updated on 14/Nov/24 $${I}=\int_{\mathrm{0}} ^{\infty} \frac{{x}^{\mathrm{2}} }{\mathrm{1}+{e}^{{x}} }{dx}\:\Rightarrow{I}=\int_{\mathrm{0}} ^{\infty} \frac{{e}^{−{x}} {x}^{\mathrm{2}} }{\mathrm{1}+{e}^{−{x}}…

Question Number 213656 by efronzo1 last updated on 12/Nov/24 Answered by golsendro last updated on 13/Nov/24 $$\left(\mathrm{i}\right)\mathrm{g}(4-\mathrm{x})=-\mathrm{g}\left(\mathrm{x}\right)$$$$\underset{0}{\stackrel{4}{\int }}\mathrm{g}\left(\mathrm{x}\right)\mathrm{dx}=\underset{0}{\stackrel{4}{\int }}\mathrm{g}(4-\mathrm{x})\mathrm{dx}$$$$\:\:\:\:\:\:\:\:\underset{\mathrm{0}}…

Question Number 213628 by Thomaseinstein last updated on 10/Nov/24 Answered by MrGaster last updated on 03/Feb/25 $$=\frac{1}{2}\left(x^4\sin \left({\tan }^{-1}\left(2x\right)\right)\right)-\frac{1}{2}{x}^3\cos \left({\tan }^{-1}\left(2x\right)\right))$$ Terms of…

Question Number 213342 by Spillover last updated on 03/Nov/24 Commented by MrGaster last updated on 03/Nov/24 $$\overline{)\begin{array}{c}\int H_x^{\sqrt{\pi }}dx=\frac{H_x^{\sqrt{\pi }+1}}{\sqrt{\pi }+1}+C\end{array}}$$ Terms of…