Question Number 120316 by Bird last updated on 30/Oct/20 $${calculate}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\frac{{xcosx}}{{cos}\left(\mathrm{2}{x}\right)}{dx} \\ $$ Answered by mathmax by abdo last updated on 30/Oct/20 $$\mathrm{let}\:\mathrm{I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…
Question Number 54777 by maxmathsup by imad last updated on 10/Feb/19 $${let}\:{u}_{{n}} =\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{sin}\left({nx}^{\mathrm{2}} \right)}{{x}^{\mathrm{2}} \:+\mathrm{6}}{dx} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:\:{u}_{{n}} \:\:\:{and}\:{lim}\:{u}_{{n}} \left({n}\rightarrow+\infty\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{nature}\:{of}\:\Sigma\:{u}_{{n}} \:\:\:{and}\:{calaculate}\:{it}. \\…
Question Number 185837 by test1234 last updated on 28/Jan/23 $$\int\frac{{cx}+{b}^{\mathrm{2}} }{\mathrm{2}{x}}−\frac{{cx}+\mathrm{2}{b}^{\mathrm{2}} }{\mathrm{4}{x}}+\frac{\left({cx}\right)^{\mathrm{2}} +\mathrm{4}{b}^{\mathrm{2}} }{\mathrm{8}{x}}{dx}=? \\ $$ Commented by MJS_new last updated on 28/Jan/23 $$\mathrm{seriously}? \\…
Question Number 185836 by greougoury555 last updated on 28/Jan/23 $$\:\left(\mathrm{1}\right)\:\:\:\:\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\frac{{dx}}{\mathrm{2}{x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{2}} +\mathrm{1}}=? \\ $$$$\left(\mathrm{2}\right)\:\underset{\mathrm{0}} {\overset{\infty} {\int}}\:\frac{{x}^{\mathrm{1}/\mathrm{4}} }{\mathrm{1}+{x}^{\mathrm{2}} }\:{dx}=? \\ $$ Answered by Ar…
Question Number 120297 by bramlexs22 last updated on 30/Oct/20 $$\:\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\:\frac{{x}\:{dx}}{\mathrm{sin}\:{x}+\mathrm{cos}\:{x}} \\ $$ Answered by Dwaipayan Shikari last updated on 30/Oct/20 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{{x}}{{sinx}+{cosx}}{dx}=\int_{\mathrm{0}}…
Question Number 54756 by Knight last updated on 10/Feb/19 $${solve} \\ $$$$\int{tan}\left({x}−\theta\right){tan}\left({x}+\theta\right){tan}\:\mathrm{2}{x}\:{dx} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 10/Feb/19 $${tan}\mathrm{2}{x}={tan}\left({x}+\theta+{x}−\theta\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:{tan}\mathrm{2}{x}=\frac{{tan}\left({x}+\theta\right)+{tan}\left({x}−\theta\right)}{\mathrm{1}−{tan}\left({x}+\theta\right){tan}\left({x}−\theta\right)} \\…
Question Number 120285 by Bird last updated on 30/Oct/20 $${calculate}\:\:\int_{\mathrm{2}} ^{\infty} \:\frac{{dx}}{\left({x}^{\mathrm{2}} −\mathrm{1}\right)^{\mathrm{2}} \left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 120283 by Bird last updated on 30/Oct/20 $${fond}\:\int_{\mathrm{2}} ^{\infty} \frac{{ln}\left(\mathrm{1}+\mathrm{3}{x}^{\mathrm{2}} \right)}{\mathrm{1}+{x}^{\mathrm{4}} }{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 185799 by Rupesh123 last updated on 27/Jan/23 Commented by SEKRET last updated on 28/Jan/23 $$\left[\boldsymbol{\mathrm{x}}\right]\:\:\rightarrow\boldsymbol{\mathrm{floor}}\left(\boldsymbol{\mathrm{x}}\right)\:\:\:\:? \\ $$$$\:\left[\mathrm{1}.\mathrm{6}\right]=\:\mathrm{1}\:\:\: \\ $$$$…. \\ $$ Answered by…
Question Number 120257 by bramlexs22 last updated on 30/Oct/20 $$\:\int\:\frac{{f}\:'\left({x}\right)}{{f}\left({x}\right)}\:=? \\ $$ Commented by TITA last updated on 30/Oct/20 $${it}\:{should}\:{be}\:\int\frac{{f}^{'} \left({x}\right)}{{f}\left({x}\right)}{dx}\:{sir} \\ $$$$ \\ $$…