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Category: Integration

1-cos-x-cos-x-sin-x-1-dx-

Question Number 187898 by cortano12 last updated on 23/Feb/23 1cosxcosx+sinx1dx=? Answered by horsebrand11 last updated on 24/Feb/23 =1222cosxcosx+sin1dx=12(1cosx+sinx)(cosx+sinx1)cosx+sinx1dx$$=−\frac{\mathrm{1}}{\mathrm{2}}{x}−\frac{\mathrm{1}}{\mathrm{2}}\int\frac{\mathrm{sin}\:\frac{\mathrm{1}}{\mathrm{2}}{x}+\mathrm{cos}\:\frac{\mathrm{1}}{\mathrm{2}}{x}}{\mathrm{sin}\:\frac{\mathrm{1}}{\mathrm{2}}{x}−\mathrm{cos}\:\frac{\mathrm{1}}{\mathrm{2}}{x}}\:{dx} \