Question Number 184514 by BOYQOBILOV last updated on 08/Jan/23 Answered by SEKRET last updated on 19/Jan/23 $$\:\:\:\boldsymbol{\mathrm{t}}\:=\:\boldsymbol{\mathrm{x}}+\sqrt{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{1}}\:\:\:\:\:\:\:\:\:/_{\mathrm{0}} ^{\:\:\:\mathrm{1}} \rightarrow/_{\mathrm{1}} ^{\:\:\mathrm{1}+\sqrt{\mathrm{2}}} \\ $$$$\:\:\:\boldsymbol{\mathrm{dt}}=\:\mathrm{1}+\frac{\boldsymbol{\mathrm{x}}}{\:\sqrt{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{1}}}\:\boldsymbol{\mathrm{dx}}=\:\frac{\boldsymbol{\mathrm{x}}+\sqrt{\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{1}}}{\:\sqrt{\boldsymbol{\mathrm{x}}^{\mathrm{2}}…
Question Number 118959 by bramlexs22 last updated on 21/Oct/20 $$\:\int\:\frac{{dx}}{{x}^{\mathrm{6}} −{x}^{\mathrm{3}} }\:? \\ $$ Answered by Dwaipayan Shikari last updated on 21/Oct/20 $$\int\frac{\mathrm{1}}{{x}^{\mathrm{3}} −\mathrm{1}}−\int\frac{\mathrm{1}}{{x}^{\mathrm{3}} }…
Question Number 118955 by Bird last updated on 21/Oct/20 $${find}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{lnx}}{{x}^{\mathrm{2}} +{x}+\mathrm{1}}{dx} \\ $$ Answered by mnjuly1970 last updated on 21/Oct/20 $$ \\ $$$${I}=\int_{\mathrm{0}}…
Question Number 53418 by Abdo msup. last updated on 21/Jan/19 $${find}\:\int_{\mathrm{0}} ^{\pi} \:\:\frac{{x}}{\mathrm{2}+{cosx}\:{sinx}}{dx} \\ $$ Commented by maxmathsup by imad last updated on 22/Jan/19 $${let}\:{I}\:=\int_{\mathrm{0}}…
Question Number 118949 by Bird last updated on 21/Oct/20 $${find}\:\int_{\mathrm{0}} ^{\infty} \:\frac{{sin}\left(\mathrm{3}{cosx}\right)}{\left({x}^{\mathrm{2}} +\mathrm{4}\right)^{\mathrm{2}} }{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 118934 by Riteshgoyal last updated on 20/Oct/20 $$ \\ $$$$ \\ $$$${I}=\int_{\mathrm{0}} ^{\infty} \:\frac{{lnx}}{{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{4}}\:{dx} \\ $$$${put}\:{x}+\mathrm{1}=\sqrt{\mathrm{3}}\:{tan}\theta \\ $$$${I}=\int_{\mathrm{0}} ^{\pi/\mathrm{2}} \:\frac{{ln}\left(\sqrt{\mathrm{3}}\:{tan}\theta−\mathrm{1}\right)}{\mathrm{3}\left({sec}^{\mathrm{2}} \theta\right)}\:\sqrt{\mathrm{3}}\:{sec}^{\mathrm{2}} \theta{d}\theta…
Question Number 118928 by mnjuly1970 last updated on 20/Oct/20 Commented by prakash jain last updated on 20/Oct/20 $$\mathrm{Suggestion}:\:\:\mathrm{attach}\:\mathrm{image}\:\mathrm{to} \\ $$$$\mathrm{original}\:\mathrm{question}\:\mathrm{as}\:\mathrm{answer}. \\ $$ Commented by mnjuly1970…
Question Number 118927 by mnjuly1970 last updated on 20/Oct/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 118924 by mnjuly1970 last updated on 21/Oct/20 $$\:\:\:\:\:\:\:\:\:…\:{advanced}\:{calculus}… \\ $$$$\:\:\:\:{prove}\:{that}\::: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} {H}_{{n}} }{{n}^{\mathrm{2}} }\:=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{ln}\left(\mathrm{1}−{x}\right){ln}\left(\mathrm{1}+{x}\right)\:\:}{{x}}{dx}\:\: \\ $$$$\:\:\:\:\:{note}\:::\:{H}_{{n}} =\underset{{k}=\mathrm{1}} {\overset{{n}}…
Question Number 53378 by Necxx last updated on 21/Jan/19 $${if}\:{u}={e}^{{xyz}} \:{then}\:{u}_{{xyx}} =? \\ $$$$\left.{a}\left.\right){u}\left(\left({xyz}\right)^{\mathrm{2}} +\mathrm{3}{xyz}+\mathrm{1}\right)\:{b}\right){u}\left(\mathrm{3}\left({xyz}\right)^{\mathrm{2}} +\mathrm{1}\right) \\ $$$$\left.{c}\right){u}\left(\left({xyz}\right)^{\mathrm{2}} +\mathrm{2}{yz}+\mathrm{1}\right) \\ $$$$ \\ $$$${please}\:{help} \\ $$…