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Category: Integration

Question-120059

Question Number 120059 by A8;15: last updated on 29/Oct/20 Answered by Lordose last updated on 29/Oct/20 Firstly,computetheindefiniteintegralI=xsec(2x)dx=14asec(a)da{a=2x}I=14(alntan(a2+π4)lntan(a2+π4)da){IBP}$$\mathrm{set}\:\frac{\mathrm{a}}{\mathrm{2}}\:+\:\frac{\pi}{\mathrm{4}}\:=\:\mathrm{y}\:\Rightarrow\:\mathrm{da}=\mathrm{2dy}…